Optics Problem: Find Smallest Refractive Index of Slab

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To determine the smallest refractive index of a rectangular slab that allows all incident light to emerge from the opposite face, total internal reflection must occur at specific angles. The critical angle, denoted as θ_c, is essential in this scenario, leading to the condition that the angle of incidence must exceed θ_c for total internal reflection. The relationship between the angle of refraction and the refractive index indicates that n must be greater than sec(r), where r is the angle of incidence. The discussion emphasizes re-evaluating the maximum angle r in terms of arc-sin functions to derive a valid refractive index. Ultimately, the solution reveals that the refractive index cannot be infinite, prompting a more precise calculation to find the correct value.
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Homework Statement


Light falls on the surface AB of a rectangular slab from air. Determine the smallest refractive index n that the material of the slab can have so that all incident light emerges from the opposite face CD.
upload_2015-6-9_20-39-0.png


Homework Equations

The Attempt at a Solution


Let's think about this case:
upload_2015-6-9_20-49-45.png

There must be total internal reflection at Q and S.
That means, ##90-r>\theta _c## [##\theta _c## is the critical angle]
## sin(90-r)>sin \theta _c##
##cos r > \frac{1}{n}## [## sin \theta _c = \frac {1}{n}##]
##n>sec(r)##
But, the maximum value of ##sec(r)## is infinite.
That means n should be infinite.
But that is not the answer.
 
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Try it again. Write down the maximum ##r## in terms of arc-sin of something. Write down ##\theta_C## in terms of arc-sin of something. Then write down ##90-r > \theta_C## in terms of these arc-sin formulas. Don't forget that air has an index of refraction very close to 1. See what you get.
 
I have got the answer. :)
 
..
 
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