- #1
Fairway
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Homework Statement
Hey guys, I have lab result here for Distribution of coefficient for the solid between water and metylene chloride
Benzoic Acid: 5mg (Weight of solute in methylene chloride)
45mg (Weight of the solute in water )
Succinic Acid: 1mg (Weight of solute in methylene chloride)
49mg (Weight of the solute in water)
Sodium Benzoate: none ( Weight of solute in methylene )
50mg (Weight of the solute in water)
Homework Equations
Becaue the volume of methylene chloride and water (2mL each) are the same in my lab,
K (distribution of coefficient)
= (the weight of the solute in methylene chloride)/ (the weight of solute in water)
The Attempt at a Solution
Benzoic Acid: K=5/45=0.11
Succinic Acid: K=1/49=0.02
Sodium Benzoate: K=0/50=0
Well, I just did what the equation say that but I'm not so sure why the values of K are so small number campare to caffeine K is 4.6 between methylene chloride and water. Thank you so much in advance.