MHB Partial fraction decomposition

AI Thread Summary
The discussion focuses on expressing rational functions as partial fractions. For the first example, the expression $$\frac{3x+4}{x^2+3x+2}$$ is decomposed into $$\frac{2}{x+2}+\frac{1}{x+1}$$ after factoring the denominator. The participants are expected to apply similar methods for the other two expressions involving more complex denominators. The conversation emphasizes understanding the structure of partial fraction decomposition and the steps involved in simplifying these rational functions. Overall, the thread aims to clarify the process of partial fraction decomposition for various rational expressions.
Jordan1994
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Q3.) Express as partial fractions.

a) $$\frac{3x+4}{x^2+3x+2}$$

b) $$\frac{5x^2+5x+8}{(x+2)\left(x^2+2 \right)}$$

c) $$\frac{x^2+15x+21}{(x+2)^2(x-3)}$$
 
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Let's begin with a). Can you state the form the partial fraction will take?
 
Here's a) without the full method:

$$\begin{align*}
\frac{3x+4}{{{x}^{2}}+3x+2}&=\frac{3x+4}{(x+1)(x+2)} \\
& =\frac{2x+2+x+2}{(x+1)(x+2)} \\
& =\frac{2(x+1)+x+2}{(x+1)(x+2)} \\
& =\frac{2}{x+2}+\frac{1}{x+1}. \\
\end{align*}$$
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

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