Particle Momentum and Position Calculation in Heisenberg Picture

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Let,s suppose we have a particle moving under a potential V:
By Heisenberg picture we know that:

\frac{dx}{dt}=p/m

so if we knew x(t) and x(t+h) we could calculate the expresion:

x(t+\epsilon)-x(t)=p\epsilon/m

so knowing x(t) and x(t+e) we could calculate the momentum of the particle:
 
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eljose said:
Let,s suppose we have a particle moving under a potential V:
By Heisenberg picture we know that:

\frac{dx}{dt}=p/m

so if we knew x(t) and x(t+h) we could calculate the expresion:

x(t+\epsilon)-x(t)=p\epsilon/m

so knowing x(t) and x(t+e) we could calculate the momentum of the particle:

Please do not mix the differential equation between operators and eigenvalues. They are completely different.


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