Path difference and phase difference.

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Path difference refers to the distance a light wave travels from its source to an observer, which can result in different wave phases reaching the observer, such as a crest at one ear and a trough at another, equating to a half wavelength difference. Phase difference, on the other hand, is illustrated by the relationship between waves, such as a cosine and sine wave being 90 degrees out of sync, leading to destructive interference. The equation relating phase difference to path difference is given by phase difference = (2π/λ) * path difference. When considering optical thickness, the phase delay can become complex, especially with varying refractive indices or wavelengths. Ultimately, while path and phase differences are distinct concepts, they can be equivalent under certain conditions involving ray propagation.
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Pardon the pun, but what's the difference between path difference and phase difference (when talking about interfering light waves)?
 
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Path difference is the distance one wave (from a coherent source) has to travel from its source to the observer. ie one observers ear may receive the crest and the other ear receive the trough. this would give a path difference of 1/2 wavelength.
Phase difference is best understood by considering a cosine wave and a sine wave. they are 90degrees out of 'synch' with each other and would produce destructive interference.
i hope someone with more brains than me can clarify your quandary. I think i am corect but i am sure someone here can be more specific.
 
bootsam said:
Path difference is the distance one wave (from a coherent source) has to travel from its source to the observer. ie one observers ear may receive the crest and the other ear receive the trough. this would give a path difference of 1/2 wavelength.
Phase difference is best understood by considering a cosine wave and a sine wave. they are 90degrees out of 'synch' with each other and would produce destructive interference.
i hope someone with more brains than me can clarify your quandary. I think i am corect but i am sure someone here can be more specific.

I believe the equation would be phase difference = 2pi/lambda*path difference
 
As a beam traverses space, the phase of a ray goes as \phi (z) = k n z, where k is the wavevector, n the refractive index, and z the distance. The quantity nz (or nd, where d is the thickness of an object) is referred to as the optical thickness. It's easy to make the sitation more complicated- make the refractive index vary with location, for example. Or make it vary with wavelength. Then the phase delay *relative to another ray*, which is the important thing, is given by more complex versions of the above formula.

Even so, there is no difference between path and phase difference, when you are able to sensibly speak of rays. This is not always the case- strongly focused light, for example. Simply considering polarization can create difficulties, forcing you to keep track of the propogation axes by hand.
 
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