Period for electromagnetic waves

AI Thread Summary
The discussion focuses on understanding the relationship between the period, frequency, and wavelength of electromagnetic waves. The period is the time for one complete oscillation, while frequency is the number of oscillations per second, with an inverse relationship between them. The speed of electromagnetic waves, such as light, varies with the medium, affecting the wavelength accordingly. For waves in different mediums, the refractive index plays a crucial role in determining the speed and wavelength. Unit analysis is emphasized as a useful method for solving related problems and understanding these concepts.
convict11
Messages
7
Reaction score
0
Hi, I have a couple of questions here I am having a little bit of difficulty with.

1) What is the wavelength of an X-ray that has a period of 1.30x10e-10s?

2) A certian EMR has a wavelength of 2.14x10e-5m in air. What is the wavelength is water(n = 1.33)?

I am not looking for the answers as I prefer to be able to understand the questions and how the answers are correct but I have searched the the textbook on this unit about magnetic fields and electric fields but can not find anything of wavelengths and periods. If anyone could tell me the equation to use or anything it would be great

All I know is that Speed of wave = Frequency * Wavelength

Is the period the frequency? and the speed of wave would be the speed of light?
 
Physics news on Phys.org
convict11 said:
Is the period the frequency?
Almost. The frequency is how many oscillations the wave goes through in a second. The period is the time it takes the wave to complete one oscillation. A little proportionality relation shows that

\frac{f}{1s}=\frac{1}{T}

where T is the period, and f the frequency.


convict11 said:
and the speed of wave would be the speed of light?
Yes, but the speed of light varies depending on the medium it travels in. You ought be have a formula relating speed of light of wavelenght as a function of the refractive index n somewhere in your notes or book.
 
In order to understand some of the methods of solving the questions you asked, it is often very helpful to do a unit analysis on a piece of paper. If you know the units of certain variables (e.g. frequency, period, etc) it is often very simple to see the relationship. For instance, if you know the frequency is in the units [1/s] and that period is in the units , it's easy to see that there's an inverse relationship.

You noted that v=f\lambda. If you do a unit analysis on that, you see that you will get [m/s]=[1/s][m], an the units work out to equal each other. If you're ever stumped as to how an equaton should look, or which variables you might need to use, or you have a question along the lines of "is the period the frequency," a unit analysis can often provide a quick and easy answer.

In response to your second problem, you have an index of refraction n. n is defined as the ratio of the speed of light in vacuum to the speed of light in the medium in question. In this case, the speed of light in vacuum is 1.33 times faster than the speed of light in the medium. This essentially means that all of the waves will propogate at c/1.33 through the medium, and therefore the wavelengths will also be that much smaller. It's a simple multiplication/division factor on \lambda
 
Thanks a lot

Thanks for the reply's guys
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top