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crosbykins
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URGENT physics find angle of inclined plane! help!?
A block slides down an inclined plane at a constant velocity of 0.14m/s. The coefficient of kinetic friction is 0.45. What is the angle of inclination?
Fnetx = Fk -mgsintheta
Fnety = FN -mgcostheta
FN-mgcosΘ = 0
FN =mgcosΘ
FN µK –mgsinΘ =0
FN = mgsinΘ/.45
mgcosΘ = mgsinΘ/.45
.45 = mgsinΘ/ mgcosΘ
.45 = tanΘ
tan-1.45 =Θ
24⁰ =Θ
Is this correct? What I don't understand is that shouldn't Fnetx include an Fapp? The question doesn't give a value for Fapp so I don't how you would use it to find the answer.
Homework Statement
A block slides down an inclined plane at a constant velocity of 0.14m/s. The coefficient of kinetic friction is 0.45. What is the angle of inclination?
Homework Equations
Fnetx = Fk -mgsintheta
Fnety = FN -mgcostheta
The Attempt at a Solution
FN-mgcosΘ = 0
FN =mgcosΘ
FN µK –mgsinΘ =0
FN = mgsinΘ/.45
mgcosΘ = mgsinΘ/.45
.45 = mgsinΘ/ mgcosΘ
.45 = tanΘ
tan-1.45 =Θ
24⁰ =Θ
Is this correct? What I don't understand is that shouldn't Fnetx include an Fapp? The question doesn't give a value for Fapp so I don't how you would use it to find the answer.