Physics Kinimatics/Energy Question

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Increasing the speed of a car by 40% results in a significant increase in its minimum braking distance. The kinetic energy equation, K=1/2 mv^2, indicates that braking distance is proportional to the square of the velocity. By establishing a ratio based on the increased speed, the new braking distance can be derived without needing specific values for mass or gravity. The discussion emphasizes the importance of using ratios to simplify the problem. Understanding these relationships is crucial for solving kinematics and energy questions effectively.
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If the speed of a car is increased by 40%, by what factor will its minimum braking distance be increased, assuming all else is the same? Ignore the driver's reaction time.


Homework Equations


K=1/2 m v^2
w=fd



The Attempt at a Solution


well i set kenitic energy to work so i got 1/2mv^2 = Fd, the force acting on the car is friction i then rewrote equation to V^2 / (2MG) = D, i got about 1.4 when i set velocity mass and gravity to 1. Didnt show up correctly on my webassign any suggestions?
 
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I would suggest that since you don't know velocity or mass initially that you don't arbitrarily assign them to values. However, what you DO know is by what factor it was increased from the initial value. Which means you can set up a ratio given that you know it takes distance D to stop for velocity V, you then set up your equation with your new velocity (1.4*V) and find the scaling factor in front of D. Those other values should all cancel out if you take it as a ratio.

Hope this helps.
 
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