Platinum ion electron configuration

In summary, The electron configuration of platinum ion (Pt ion) is [Xe]4f14 5d9 6s1. This means that platinum ion has lost one electron from its outermost 6s orbital and has the same electron configuration as xenon (Xe) with a full 4f subshell and 9 electrons in the 5d subshell. Platinum ion has 1 valence electron, which is in the 6s orbital. The electron configuration of platinum ion is significant because it determines the chemical and physical properties of the ion. The electron configuration of platinum ion is almost the same as that of platinum, with the only difference being one less electron in the outermost 6s orbital.
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Homework Statement
Write the electron configuration for platinum ion in Pt(NH3)2Cl2.
Relevant Equations
electron configuration
The answer is [Xe] 4f14 5d8. Why does platinum (and other 6th and 7th period d-block elements) have 4f14 instead of 4f7? Thanks.
 
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How many electrons does your configuration have? How many does a platinum atom need to be neutral?
 

FAQ: Platinum ion electron configuration

What is the electron configuration of platinum ion?

The electron configuration of platinum ion is [Xe] 4f14 5d9.

How many valence electrons does platinum ion have?

Platinum ion has 9 valence electrons.

Why does platinum ion have a different electron configuration than neutral platinum?

Platinum ion has a different electron configuration because it has lost one or more electrons, resulting in a different number of electrons in its energy levels.

What is the significance of platinum ion's electron configuration?

The electron configuration of platinum ion determines its chemical and physical properties, such as its reactivity and bonding abilities.

How does platinum ion's electron configuration affect its use in industrial processes?

The electron configuration of platinum ion makes it a highly stable and efficient catalyst, making it useful in various industrial processes such as petroleum refining and chemical synthesis.

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