- #1
hornekat
- 1
- 0
Please help me solve this differential equation for the initial condition (0,-1):
dx/dy = ((1+x^2)^(1/2))/(xy^3)
I think I'm doing something wrong because I end up with
((x^2)(y^3))/2 = ((x^2)+y)^(1/2) + c,
but when plugging in the initial condition it ends up being the square root of negative one.
Please help, thank you!
dx/dy = ((1+x^2)^(1/2))/(xy^3)
I think I'm doing something wrong because I end up with
((x^2)(y^3))/2 = ((x^2)+y)^(1/2) + c,
but when plugging in the initial condition it ends up being the square root of negative one.
Please help, thank you!