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What exactly is a "margin of error" intended to be for a poll?
Is it a one sigma number? A 90 or 95% CL? An educated guess?
As I understand it, this number is reported on each result - i.e. if the poll says Smith and Jones each have 50% support with a 5% MOE, the "true" result can be anywhere between 45-55 and 55-45. So when the pundits say "the difference is less than the MOE" they really mean "less than twice the MOE."
Also as I understand it, polls need to be corrected for over and undersampling various subpopulations. (e.g. people with cell phones and no landline tend to be undersampled) This correction should form part of the MOE. But it surely is not distributed as a Gaussian. We could even argue about whether it is distributed at all!
When aggregators combine polls, they surely look at (and hopefully weight appropriately) the MOE. Do they also consider how accurate the MOE has been in the past? If a pollster systematically underestimates their MOE, that does not make it a better poll for sure. And vice versa.
Is it a one sigma number? A 90 or 95% CL? An educated guess?
As I understand it, this number is reported on each result - i.e. if the poll says Smith and Jones each have 50% support with a 5% MOE, the "true" result can be anywhere between 45-55 and 55-45. So when the pundits say "the difference is less than the MOE" they really mean "less than twice the MOE."
Also as I understand it, polls need to be corrected for over and undersampling various subpopulations. (e.g. people with cell phones and no landline tend to be undersampled) This correction should form part of the MOE. But it surely is not distributed as a Gaussian. We could even argue about whether it is distributed at all!
When aggregators combine polls, they surely look at (and hopefully weight appropriately) the MOE. Do they also consider how accurate the MOE has been in the past? If a pollster systematically underestimates their MOE, that does not make it a better poll for sure. And vice versa.