- #71
fog37
- 1,569
- 108
Ok, thanks that is progress.
What about two independent fermions having a total antisymmetric wavefunction $$\Psi(x_1, x_2)=\psi_{a}(x_1) \psi_{b}(x_2)-\psi_a(x_2) \psi_b(x_1)$$?
This is the sum of two products not a single product but it does not mean entanglement, correct? Why not?
What about two independent fermions having a total antisymmetric wavefunction $$\Psi(x_1, x_2)=\psi_{a}(x_1) \psi_{b}(x_2)-\psi_a(x_2) \psi_b(x_1)$$?
This is the sum of two products not a single product but it does not mean entanglement, correct? Why not?