Positive and negative square roots

AI Thread Summary
Determining positive and negative square roots in equations requires careful consideration of the context, especially when the equation is complex. Substituting solutions back into the original equation is essential for verification, as squaring both sides can lead to non-equivalent results. In the discussed example, the equation +sqrt(...)=1-x yields two real roots, while -sqrt(...)=1-x has no real or complex roots. The necessity of verification highlights the importance of understanding which roots are valid in the original equation. Ultimately, substituting solutions is the most reliable method to confirm their validity.
kevs926
Messages
13
Reaction score
0
how to determine which is the answer to positive sqrt and negative sqrt in this problem?

substituting works but what if the equation is very long and you can't use calcu or computers

http://i.imgur.com/SkcQZ.png

also is there a way to solve this without squaring both sides?
 
Mathematics news on Phys.org
actually both are positive sqrt answers because there is no negative sqrt answer

also i think negative sqrt answers will come naturally.

but still, is there a way to solve this without squaring both sides?
 
This is why one has to do verification after solving an equation (unless he can guarantee that every step of the solution process is an equivalence ). In the case we consider only the negative or only the positive sqrt, when we square both sides we don't produce an equivalence. In the case we take both then we have an equivalence but there is no way to know which root belongs to which case unless we substitute the solutions to the original equation.

In this example the equation +sqrt(...)=1-x has two roots in R but the equation -sqrt(...)=1-x has no root in R (and no root in C also). I don't see other way to show the latter result, other than squaring, finding the two roots and then by substitution in the original equation to find out that they don't verify it.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

Similar threads

Back
Top