- #1
mcastillo356
Gold Member
- 593
- 321
Hi PF
I've got the 6th Spanish edition of "Calculus", by Robert A. Adams. At the chapter 3.5, "Inverse trigonometric functions", few lines below "Definition 12 The inverse function of cosine cos-1x or arccos x ", it says:
"The derivative of cos-1x is the negative of that of sin-1x (why?):
$$\dfrac{d}{dx}\cos^{-1}x=\dfrac{1}{\sqrt{1-x^2}}$$
This last is a typo; there is a minus sign forgotten, isn't it?
Greetings
I've got the 6th Spanish edition of "Calculus", by Robert A. Adams. At the chapter 3.5, "Inverse trigonometric functions", few lines below "Definition 12 The inverse function of cosine cos-1x or arccos x ", it says:
"The derivative of cos-1x is the negative of that of sin-1x (why?):
$$\dfrac{d}{dx}\cos^{-1}x=\dfrac{1}{\sqrt{1-x^2}}$$
This last is a typo; there is a minus sign forgotten, isn't it?
Greetings