Power Loss or gain from a fluid flow

AI Thread Summary
Calculating power loss or gain in fluid flow requires understanding both the mass flow and pressure differences, but the approach varies for incompressible versus compressible fluids. For incompressible fluids, the formula (volume flow)*(pressure difference) can be applied, while compressible fluids necessitate more complex calculations involving temperature and enthalpy changes. Accurate energy change assessments require evaluating fluid properties at both inlet and outlet, particularly when dealing with gases or phase transitions. In scenarios like flow through a venturi device, using mass flow and enthalpy change is appropriate, but temperature data is crucial for precise calculations. Without temperature information, alternative methods using pressure data may be limited in effectiveness.
99percent
Messages
3
Reaction score
0
Hi guys,

I have quick question about calculating the power lost in fluid flow.

So imagine there is a simple setup as in the attached image, where you know the mass flow in and out, pressures at inlet and outlet and the temperature at the inlet.

Is the equation to find the power lost or gained by the flow just (volume flow)*(pressure difference)?

I know that you can use this to calculate the power required for a pump using liquids, does this also work for gases?

Thanks!
 

Attachments

  • Untitled.png
    Untitled.png
    859 bytes · Views: 579
Engineering news on Phys.org
Simple formula only works with incompressible fluids and low velocities .

Even if doing only simple tests or calculations then at least two properties of fluid really need to be evaluated at inlet and outlet to get energy change .

As flow regime gets more complex and compressiblity and temperature changes become more relevant then more complex calculations are nescessary .

Some fluids like vapours which might go through phase transition are even more complicated to test or analyse .

All covered in Thermodynamics and Fluid Flow theory but you'll have to study that .
 
  • Like
Likes 99percent and billy_joule
Thanks very much for your answer and explanation!

Edit: What equation would be best to use? Would I also need to know the temperature at both the inlet and the outlet to get energy change for compressible flow?
 
Last edited:
99percent said:
Thanks very much for your answer and explanation!

Edit: What equation would be best to use? Would I also need to know the temperature at both the inlet and the outlet to get energy change for compressible flow?

Depends on what type of flow you are actually trying to monitor . Give me a specific example and I'll get back to you .
 
Nidum said:
Depends on what type of flow you are actually trying to monitor . Give me a specific example and I'll get back to you .

I am basically looking at a flow before and after a venturi like device, however the inlet and outlet diameters are different.

Could I just use the mass flow* (enthalpy change)to get the power? where the enthalpy is cp*T?

If I don't have the temperatures, is there a way of just working it out using the pressures?
 
Here's a video by “driving 4 answers” who seems to me to be well versed on the details of Internal Combustion engines. The video does cover something that's a bit shrouded in 'conspiracy theory', and he touches on that, but of course for phys.org, I'm only interested in the actual science involved. He analyzes the claim of achieving 100 mpg with a 427 cubic inch V8 1970 Ford Galaxy in 1977. Only the fuel supply system was modified. I was surprised that he feels the claim could have been...
TL;DR Summary: Heard in the news about using sonar to locate the sub Hello : After the sinking of the ship near the Greek shores , carrying of alot of people , there was another accident that include 5 tourists and a submarine visiting the titanic , which went missing Some technical notes captured my attention, that there us few sonar devices are hearing sounds repeated every 30 seconds , but they are not able to locate the source Is it possible that the sound waves are reflecting from...
Back
Top