Probabilities of certain events in a lucky wheel game

In summary, the conversation discusses a game with a wheel of fortune with ten equal sectors, five labelled with 1, three with 2, and two with 3. The game is played with pairs of candidates who spin the wheel, and the winner is the one with the higher number. The minimum number of candidate pairs needed to ensure at least one draw with a probability of 0.95 is 7. The probability of at most 143 out of 376 matches ending in a draw is found using the binomial theorem.
  • #1
emmi2104
1
0
Given information:
A wheel of fortune with ten equal sectors is used for a candidate game. Five of these sectors are labelled only with the number 1, three only with the number 2 and two only with the number 3.

The game for a pair of candidates is as follows: The two candidates �K1 and K2, independently of each other, each spin the wheel of fortune once. The winner is the candidate who has "spun" the higher number. If the numbers are the same, the game ends in a draw.

  • f) The game described above is played with 𝑛 pairs of candidates. What is the minimum number of candidate pairs with which the game must be played so that with a probability of at least 0.95 at least one game ends in a draw?
and
  • h) With what probability 𝑝 do at most 143 of the 376 matches end in a draw?
 
Last edited:
Mathematics news on Phys.org
  • #2
I see this is an old unanswered question. Perhaps it was a homework problem at one time. I would start by finding out the probability of (not a tie) in a single match.
 
  • #3
That would be 1 - (0.5^2+0.3^2+0.2^2) = 0.62
Now what's the minimum value of n s.t. 0.62^n <= 0.05? Trial and error (or taking the log of .05 base 0.62 and rounding up) says 7

Does h require the binomial theorem?
 

FAQ: Probabilities of certain events in a lucky wheel game

What is a lucky wheel game?

A lucky wheel game is a game of chance where players spin a wheel with different sections, each representing a prize or outcome. The player wins the prize or outcome that the wheel lands on after spinning.

How are probabilities calculated in a lucky wheel game?

The probabilities in a lucky wheel game are calculated by dividing the number of desired outcomes by the total number of possible outcomes. For example, if there are 10 sections on the wheel and 2 of them represent a prize, the probability of winning that prize would be 2/10 or 20%.

Can probabilities change in a lucky wheel game?

Yes, probabilities can change in a lucky wheel game if the number of sections or desired outcomes on the wheel are altered. For example, if a section is added or removed, the probabilities for each outcome will change.

Is it possible to increase your chances of winning in a lucky wheel game?

Technically, no. The probabilities of winning in a lucky wheel game are based on chance and cannot be manipulated. However, some players may use strategies such as betting on multiple sections to increase their chances of winning, but this does not guarantee a win.

Are there any factors that can affect the probabilities in a lucky wheel game?

Yes, there are several factors that can affect the probabilities in a lucky wheel game. These include the number of sections on the wheel, the size and placement of the sections, and any external factors such as wind or friction that may affect the spin of the wheel.

Back
Top