Projectile Launch Speed: Solve 876j Work Homework

  • Thread starter Thread starter Chica1975
  • Start date Start date
  • Tags Tags
    Projectiles Work
AI Thread Summary
To find the launch speed of a projectile given 876 joules of work on a 0.398 kg projectile, the work-energy principle can be applied, stating that work done is equal to the change in kinetic energy (W = ΔE). The gravitational force acting on the projectile is approximately 3.9004 N. The user is struggling with the calculations and has attempted to draw a diagram to visualize the problem. They acknowledge that the work done translates entirely into kinetic energy. Further assistance is requested to solve for the launch speed.
Chica1975
Messages
63
Reaction score
0

Homework Statement


A projectile launcher did 876j of work on a .398kg projectile what is the launch speed of the projectile?


Homework Equations


W = f*d
mg = 3.9004
after that I am stuck


The Attempt at a Solution



I drew a diagram and tried a few things but am completely stuck. please help.
 
Physics news on Phys.org
Chica1975 said:

The Attempt at a Solution



I drew a diagram and tried a few things but am completely stuck. please help.

The work done is entirely kinetic :wink:
 
thanks I will look it up and try again.
 
W = F * d is only a mathematical tool to calculate how much work is done. The applicable statement of physics is W = \DeltaE
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top