MHB Proofing the Equation: (A=B Union C & B ∩ C=Ø) => (A\B=C)

  • Thread starter Thread starter Violet1
  • Start date Start date
  • Tags Tags
    Union
AI Thread Summary
The discussion revolves around proving the mathematical statement (A=B union C and B intersect C=Ø) implies (A\B=C). Participants emphasize the importance of understanding the concepts involved, suggesting the use of Venn diagrams to visualize the relationships between sets. One user points out that the original request mislabels the statement as an equation rather than a theorem. The conversation encourages a deeper exploration of formal proof techniques, with a focus on clarity and logical reasoning. Overall, the thread highlights the value of visual aids and precise language in mathematical discussions.
Violet1
Messages
2
Reaction score
0
Hi! I need help for this:
Proof equation: (A=B union C and B intersect C=empty set)=>(A\B=C)!

Tnx! :o
 
Mathematics news on Phys.org
Hi and welcome to the forum.

What kind of help do you need? Surely you understand that if you take all women from a group of adults, you'll get all men and only men.

Please take some time to read the http://mathhelpboards.com/rules/, especially rule #11. Also, what you are proving is not an equation; it's a statement (claim, proposition, theorem) in the form of an implication. Finally, "proof" is a noun, and the corresponding verb is "prove".
 
Heh :D Perhaps Evengy overdid it a bit.

Okay, try drawing the Venn diagram. What do you observe? Do you see how obvious it is? Can you now sketch out a formal proof?

Balarka
.
 
:(
mathbalarka said:
Heh :D Perhaps Evengy overdid it a bit.

Okay, try drawing the Venn diagram. What do you observe? Do you see how obvious it is? Can you now sketch out a formal proof?

Balarka
.

Thanks Balarka! When I draw Venn diagram, everything is clear! But I can't sketch out a formal proof! :(
 
Last edited by a moderator:
Perhaps you could at least show us what approach you took?
 

Thread 'Trigonometry problem of interest'

Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
View full post »

Similar threads

I On a proof of the converse of the supporting hyperplane theorem
Replies
9
Views
2K
MHB Find P(Q') B) P(Q union R) C) P(R')
Replies
2
Views
2K
MHB Re: Union and Intersection of Sets
Replies
3
Views
2K
B Complete the square, yes, but what does it mean?
Replies
19
Views
3K
I Solving a system of equations with 5 unknowns
Replies
10
Views
1K
MHB 411.1.3.15 Prove A\cap(B/C)=(A\cap B)/(A\cap C)
Replies
2
Views
2K
MHB Interval of eigenvalues using Gershgorin circles
Replies
3
Views
2K
MHB Find All Integers for Equal Sum Disjoint Union Sets
Replies
4
Views
1K
I Proof of Differences of Odd Powers
Replies
11
Views
2K
MHB Union/Intersection of fractions or percentages
Replies
6
Views
9K

Hot Threads

Recent Insights

Back
Top