Proton moving in magnetic field

AI Thread Summary
A proton traveling in the +z direction at 4105 m/s is subjected to a magnetic field of 0.25 T in the +x direction. The force on the proton can be determined using the equation F = qvB, where q is the charge of the proton, v is its velocity, and B is the magnetic field strength. The right-hand rule helps establish the direction of the force, which is perpendicular to both the velocity and the magnetic field. Confusion arises regarding the application of the left-hand rule, but the correct approach is to consistently use the right-hand rule for protons. Ultimately, the discussion emphasizes the importance of correctly applying these rules to find both the direction and magnitude of the force on the proton.
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Homework Statement


At a particular instant a proton is traveling in the +z direction, with speed 4105 m/s. At the location of the proton there is a magnetic field of magnitude 0.25 T in the +x direction, due to current running in a nearby coil.
what is the direction and magnitude of force on the proton?

Homework Equations


none i think?


The Attempt at a Solution


Do you use the right hand rule possibly?
 
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The right hand rule can give you the direction of the force, but not the magnitude.

What equation do you know that gives the force on a charged particle of charge q moving with velocity v in a magnetic field of strength B?
 
Try to find out the formula for the force on a charged particle in a magnetic field. The direction of the field is given by the left hand rule.
 
the equation is F=qvB but then using the left hand rule since it is a proton would give me negative y direction if I'm not mistaken and that is incorrect?
 
You can use either right handed screw rule or Flemming's left hand rule.
 
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