Prove: p - q Divides p - 1 Implies q - p Divides q - 1

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In summary, if p - q divides p - 1, then k*(p - q) = p - 1. To prove that q - p divides q - 1, we can manipulate the equation p·(k - 1) = k·q - 1 to give q - 1 on the right side and rearrange the left side to get q - p. This shows that q - p divides q - 1, completing the proof.
  • #1
Dustinsfl
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Let p,q ∈ ℤ+ , p < q. Prove that if p - q divides p - 1, then q - p divides q - 1.

So if p - q divides p - 1, then k*(p - q) = p - 1.

Now what?
 
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  • #2


Now you should relate the conclusion you want to the hypothesis. How can you rewrite q -1 to introduce the p - 1 term (and why would this help you).
 
  • #3


Multiply through by k and then bring over the p from the right side (and simplify that with kp). Then subtract both sides by q and rearrange.
 
  • #4


By doing that, it only yields k·p - k·q - p = p·(k - 1) - k·q ⇒ p·(k - 1) = k·q - 1. How can that be manipulated to fit the conclusion?
 
  • #5


What I was thinking was: p·(k - 1) - k·q = -1, then add q to both sides to give q-1 on the right side and simplify -kq + q. Then rearrange the resulting left side of the equation.
 

FAQ: Prove: p - q Divides p - 1 Implies q - p Divides q - 1

What is the meaning of the statement "p - q Divides p - 1 Implies q - p Divides q - 1"?

This statement is a mathematical proposition that states if the difference between two numbers, p and q, is a factor of the difference between p and 1, then the difference between q and p is also a factor of the difference between q and 1.

What does it mean for a number to "divide" another number?

When we say that one number divides another, it means that the first number is a factor of the second number. In other words, the second number can be evenly divided by the first number without any remainder.

What is the significance of this statement in mathematics?

This statement is significant in mathematics because it is a conditional statement, which means that it can be used in proofs to show that one statement logically follows from another. In this case, it can be used to prove certain properties of divisibility.

Can you provide an example of how this statement can be used in a proof?

Sure, for example, if we let p = 6 and q = 2, then the statement becomes "6 - 2 Divides 6 - 1 Implies 2 - 6 Divides 2 - 1". We can then see that 6 - 2 = 4, which is a factor of 6 - 1 = 5. This proves the first part of the statement. Then, 2 - 6 = -4, which is also a factor of 2 - 1 = 1. This proves the second part of the statement. Therefore, the statement is true for these values of p and q.

Are there any exceptions to this statement?

Yes, there are exceptions to this statement. For example, if p = 2 and q = 1, then the statement becomes "2 - 1 Divides 2 - 1 Implies 1 - 2 Divides 1 - 1". In this case, the statement is not true because 2 - 1 = 1 is not a factor of 2 - 1 = 1, and 1 - 2 = -1 is not a factor of 1 - 1 = 0. So, we cannot conclude that q - p divides q - 1 in this case.

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