- #1
solakis1
- 422
- 0
Given the definition: \(\displaystyle A^{n+1}=A^n\cup A\) then prove that:
\(\displaystyle (A\cup B)^n =(A\cup B)\cup(A\cap B)\) for all natural N0s n
\(\displaystyle (A\cup B)^n =(A\cup B)\cup(A\cap B)\) for all natural N0s n