Proving g(x) is continuous over interval (-∞,-2)

In summary, when referring to the interval from negative infinity to -2, the notation -∞ < a < -2 or a ∈ (-∞, -2) is used and it conveys the same information. This notation typically includes a parenthesis to indicate an excluded endpoint and a bracket for an included endpoint. The use of "For" in a compound inequality is not necessary.
  • #1
member 731016
Homework Statement
Please see below
Relevant Equations
Please see below
For number 18,
1676597607436.png

The solution is,
1676597636101.png

However, should they not write "For ## -∞ < a < -2##" since ##a ≠ -∞## (infinity is not a number)?

Many thanks!
 
Physics news on Phys.org
  • #2
##a## is a number, so can't be negative infinity.

In particular, ##a\in [-\infty,-2)## isn't really a meaningful thing outside of people abusing notation.
 
  • Like
Likes member 731016
  • #3
Office_Shredder said:
##a## is a number, so can't be negative infinity.

In particular, ##a\in [-\infty,-2)## isn't really a meaningful thing outside of people abusing notation.
Thank you for your reply @Office_Shredder !

So a better notation than ## a < -2 ## is ## -∞ < a < -2##, correct?

Many thanks!
 
  • #4
Callumnc1 said:
Thank you for your reply @Office_Shredder !

So a better notation than ## a < -2 ## is ## -∞ < a < -2##, correct?

Many thanks!
No, the ##-\infty<a## notation conveys no additional information. ##a## and ##a>-\infty## are the same thing. You can include the negative infinity, but in no sense is it better here.
 
  • Like
Likes member 731016
  • #5
Callumnc1 said:
However, should they not write "For −∞<a<−2"
##-\infty < a < -2## and ##a \in (-\infty, -2)## are two different notations that say exactly the same thing. In most of the books I've seen, interval notation, as in the 2nd example above, uses a parenthesis to indicate an endpoint that isn't included, and a bracket to indicate that an endpoint is included. I've seen other notations used, but these seem to be a lot rarer.

Also, I don't think any textbook would include "For" in a compound inequality. ##-\infty < a < -2## says everything that needs to be said.
 
  • Like
Likes member 731016
  • #6

FAQ: Proving g(x) is continuous over interval (-∞,-2)

What does it mean for a function to be continuous over an interval?

A function is continuous over an interval if, for every point within that interval, the function is defined, the limit of the function as it approaches that point exists, and the limit equals the function's value at that point. In other words, there are no breaks, jumps, or holes in the graph of the function over that interval.

What steps are involved in proving that g(x) is continuous over the interval (-∞,-2)?

To prove that g(x) is continuous over the interval (-∞,-2), you need to:1. Ensure that g(x) is defined for all x in (-∞,-2).2. Show that the limit of g(x) as x approaches any point c in (-∞,-2) exists.3. Verify that this limit equals g(c) for all c in (-∞,-2).

What are common methods to prove the continuity of a function?

Common methods to prove the continuity of a function include:1. Using the definition of continuity (limit definition).2. Applying known theorems, such as the Intermediate Value Theorem or the fact that polynomials and rational functions (where the denominator is non-zero) are continuous.3. Checking the continuity of component functions if g(x) is composed of simpler functions.

What are potential challenges in proving g(x) is continuous over (-∞,-2)?

Potential challenges include:1. Identifying points where g(x) might not be defined or might have discontinuities.2. Calculating limits, especially if g(x) involves complex expressions.3. Ensuring that all points in the interval (-∞,-2) are accounted for, particularly if the function has different forms over different subintervals.

Can a function be continuous over an interval if it has a discontinuity at a single point within that interval?

No, a function cannot be continuous over an interval if it has a discontinuity at any point within that interval. Continuity requires that the function be continuous at every point in the interval. If there is even one point where the function is not continuous, then the function is not continuous over that interval.

Back
Top