Proving on the completeness theorem of real number

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In summary, the conversation discusses various statements and properties related to sets and functions in the real number system. The completeness axiom is also mentioned, which is equivalent to the Least Upper Bound Property and the Greatest Lower Bound Property. The Monotone Property is also introduced, along with its implications on sets A and B. Finally, it is shown that if a set A has a supremum and a set B has an infimum, then the greatest lower bound of A is less than or equal to the supremum of B.
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1. Homework Statement

(1) ** Show that a function f is continuous at a point c if and only
if for every sequence (xn) of points in the domain of f such that
xn ! c we have limn!1 f(xn) = f(c) = f(limn!1 xn).
(2) Let A be a non-empty subset of R. Dene A := fxjx 2 Ag.
Show the following statements.
(a) A has a supremum if and only if A has an inmum, in
which case we have inf(A) = sup A.
(b) A has an inmum if and only if A has a supremum, in
which case we have sup(A) = inf A.
(3) Show that the completeness axiom of real number system (i.e.
the Least Upper Bound Property) is equivalent to the Greatest
Lower Bound Property: Every non-empty set A of real numbers
that has a lower bound has a greatest lower bound.
HINT: Use (2).
(4) * (Monotone Property) Suppose that A B R, where A =6 ;
and B =6 ;. Show the following statements.
(a) If B has a supremum, then A has also a supremum, and
sup A sup B.
(b) If B has an inmum, then A has also an inmum, and
inf A inf B.
(5) ** Let A and B be non-empty subsets of R such that a b for
all a 2 A and b 2 B. Show that A has a supremum and B has
an inmum, and sup A inf B



2. Homework Equations
The completeness axiom




3. The Attempt at a Solution
I am seriously clueless on how to approach... but I still tried something
But my method seems a bit weird...

 
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Show us what you have tried so that we may help you.
 

Related to Proving on the completeness theorem of real number

1. What is the completeness theorem of real numbers?

The completeness theorem of real numbers states that any nonempty set of real numbers that is bounded above must have a least upper bound, also known as a supremum. This means that there is always a real number that is larger than all the numbers in the set, but still the smallest in comparison to all other real numbers.

2. Why is the completeness theorem important?

The completeness theorem is important because it provides a foundation for the real number system and allows for the rigorous study of calculus and analysis. It also allows for the development of important mathematical concepts such as continuity and convergence.

3. How is the completeness theorem proven?

The completeness theorem is proven using the method of proof by contradiction. This involves assuming that the theorem is false and then showing that this assumption leads to a contradiction. This contradiction then proves that the theorem must be true.

4. What is the difference between completeness theorem and compactness theorem?

The completeness theorem and compactness theorem are two different theorems that both deal with sets of real numbers. The completeness theorem states that every nonempty set of real numbers that is bounded above has a least upper bound, whereas the compactness theorem states that every open cover of a set of real numbers has a finite subcover. In other words, the completeness theorem deals with bounded sets while the compactness theorem deals with open sets.

5. How does the completeness theorem relate to the axiom of completeness?

The completeness theorem is a direct consequence of the axiom of completeness, also known as the least upper bound property. The axiom of completeness states that any nonempty set of real numbers that is bounded above must have a least upper bound. The completeness theorem provides a proof for this axiom, which is one of the fundamental axioms of the real number system.

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