Proving Polynomial Property: Get Hint Here

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To prove that p(x) = f(x+a) is a polynomial of degree n for each real a, it is essential to clarify the nature of the function f. The discussion emphasizes that f must be defined as a polynomial function; otherwise, the statement does not hold true. An example is provided where if f(x) = sin(x), then p(x) = sin(x+a) is not a polynomial. Participants suggest revisiting the definitions and conditions surrounding f to correctly approach the proof. Understanding these foundational aspects is crucial for successfully proving the polynomial property.
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Homework Statement



Prove the following

For each real a, the function p given by p(x) = f(x+a) is a polynomial of degree n.

Homework Equations


Can I have a hint I have hard time starting.Thanks


The Attempt at a Solution

 
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Jbreezy said:

Homework Statement



Prove the following

For each real a, the function p given by p(x) = f(x+a) is a polynomial of degree n.

Homework Equations


Can I have a hint I have hard time starting.Thanks


The Attempt at a Solution


I think the hint would be to re-read the question and any material that is being assumed as background to it, as there has to be some condition or definition on f else it is not even true. That condition would be what you have to use.
 
For example, if f(x)= sin(x), then p(x)= sin(x+ a) is NOT a polynomial. Surely, you have misunderstood the question.
 
The working out suggests first equating ## \sqrt{i} = x + iy ## and suggests that squaring and equating real and imaginary parts of both sides results in ## \sqrt{i} = \pm (1+i)/ \sqrt{2} ## Squaring both sides results in: $$ i = (x + iy)^2 $$ $$ i = x^2 + 2ixy -y^2 $$ equating real parts gives $$ x^2 - y^2 = 0 $$ $$ (x+y)(x-y) = 0 $$ $$ x = \pm y $$ equating imaginary parts gives: $$ i = 2ixy $$ $$ 2xy = 1 $$ I'm not really sure how to proceed from here.
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