- #1
misogynisticfeminist
- 370
- 0
If I got [tex] v=u+at [/tex]
i get, [tex] \int v = \int (u+at) dt [/tex]
which is [tex] s=ut+\frac {1}{2} at^2 + C [/tex]
how do i explain away the integration constant in this derivation?
i get, [tex] \int v = \int (u+at) dt [/tex]
which is [tex] s=ut+\frac {1}{2} at^2 + C [/tex]
how do i explain away the integration constant in this derivation?