Question abou Patterson Algorithm

[juaninf]

Hi every one

In the preliminaries section, the item c), there a proposition that say: "So by our choice of g we get "\theta/p | \psi/p" whence "\theta | \psi" ". I am not understanding this propositión, Please help me

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[micromass]

That

\theta/p~\vert~\psi/p

means that there exists a c such that

c\theta/p=\psi/p

Now multiply both sides by p...

 

[juaninf]

thanks by your attention, but, a important part is: In the preliminaries section, the item c), there a proposition that say: "So by our choice of g we get "
\theta/p | \psi/p[\tex], how i use "So by our choice of g we get", Why g havenot any degree?, why choice small as posible that contravening c)?

 

[HallsofIvy]

juaninf, if you keep "bumping" your threads every few minutes, you are going to get banned.