Question about projectile motion

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In projectile motion, the vertical acceleration of an object is indeed equal to 9.81 m/s² due to gravity, assuming no air resistance. To find the initial velocity, the equation used is initial V = (X - initial X) / t. For maximum height, the formula is y = (4.9 m/s²) (t²), starting from an initial height of zero. Angles in projectile motion can be calculated using trigonometric functions such as sine, cosine, and tangent, or through the Pythagorean theorem. Understanding these principles is crucial for solving projectile motion problems effectively.
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I have a question when any object is in project motion is the vertical acceleration of the object equal to 9.81m/s^2 (gravity)?
 
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Yes - (ignoring air resistance) remember to get the signs right, it acts down!
 
Yes. (Given the usual assumptions: Near the Earth's surface; no air resistance.)
 
Doc Al said:
Yes. (Given the usual assumptions: Near the Earth's surface; no air resistance.)

I have another question what equations can I use to find intial v, the angle and maximum height on projectile motion?
 
I have another question what equations can I use to find intial v, the angle and maximum height on projectile motion?

For initial V you only need:

initial V = (X - initial X) / t


For maximum height (you are asking for final y, where initial y=0, and initial V=0) :

y = (4.9m/s^2) (t^2)


Finally, angles are found using Pythagoras theorem or sen, cos, and tan famous equations. Review your trigonometry.
 
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