Question regarding magnetic fields being unable to do work?

In summary: I look forward to reading your thoughts on it.In summary, the conversation discusses the concept of magnetic fields and the idea that a magnetic force cannot do work, only change direction. This is counter-intuitive since a magnet can cause a rapid acceleration towards a refrigerator. The conversation also mentions different models of magnetism and the debate surrounding the interaction between a magnetic field and an intrinsic magnetic moment. Ultimately, it is important to understand the concept in terms of quantum mechanics rather than trying to relate it to classical electromagnetism. Further reading and resources are provided for a deeper understanding of the topic.
  • #1
Ascendant78
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I'm currently taking Physics II and had a question. I'd ask my professor, but he's out of town until Monday and this is driving me crazy. Anyway, we recently started learning about magnetic fields. So far, I'm grasping most of it no problem. One thing that is throwing me off though is how they keep emphasizing that a magnetic force can't do work, it can only change direction. This seems counter-intuitive to me since if I let go of a magnet close to my refrigerator and it has zero initial velocity, it has a very rapid acceleration towards the refrigerator (until collision of course). If someone can help make sense of this to me, I'd appreciate it, because if that acceleration isn't coming from the magnetic force, then I'm not sure what it is that is causing it?
 
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  • #2
You should do a search. This is an oldie, but goodie. After your search you might have some more specific questions.

(When I was an undergrad I pressed multiple professors for a satisfactory answer to this and they all responded differently and in some ways, contrary to each other.)

edit - Maybe this will be interesting->
http://engagedscholarship.csuohio.edu/cgi/viewcontent.cgi?article=1071&context=sciphysics_facpub
Some of the math might be hard to follow, but that's a good paper to read if you are interested in this. If you can glean something from the introduction, post it, because I haven't read it in a few years. :)
 
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  • #3
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  • #4
Thanks for the information from both of you. I really appreciate it. I always like to make sure I have my mind fully wrapped around these things, so hopefully after going through all that both of you posted, it will.
 
  • #6
The discussions here tend to follow something of a meandering path and contain their own links to other discussions that are similarly meandering. Those who don't want to wade through the interminable links may benifit from something of an executive summary.

for a particle in a magnetic field, we have to consider two cases:
1. the particle has no intrinsic magnetic moment
2. the particle has an intrinsic magnetic moment

For these situations:
for 1. the B field does no work since the force is always perpendicular to the motion - but, recalling Newton's laws - it is the net force that does the work. The B-force can contribute to the net force in a way similar to the "normal force" in sliding-block problems.

for 2. the B field can do work as it interacts with the magnetic dipole. This is the principle behind the Stern-Gerlach experiment for eg.

Much of the debate revolves around what is "really" happening in #2. So let's be clear:

#2 is a quantum mechanical effect.
It is possible to model it as if there were an uneven charge distribution that acts as some sort of current and, thereby, obtain some hand-wavy link to pre-existing understandings of classical electromagnetism. That's not really a useful way to think about it, however, it is common in introductory e-mag courses.

Better to think of QM as a superset of the classical - seeking to understand QM in terms of classical physics will only get you tangled up.

Introductory physics texts are usually only concerned about #1 so they tend to leave off the qualification that the statement only applies to charged particles in a magnetic field. You'll notice that the same texts tend to follow the statement with examples involving only uniform magnetic fields - where there is no magnetic dipole interaction.

Students from early on are taught two different models of magnetism - in one they are encouraged to think of materials as consisting of lots of tiny magnets which are all lined up in permanent magnets and in the other they are encouraged to think in terms of tiny current loops. We get this sort of question as students struggle to find links between the models.

Further reading:
http://www.phys.ufl.edu/courses/phy2049/f07/lectures/2049_ch28B.pdf
... most of the discussions are summed up in this lecture: slide 17, in particular.

https://www.physicsforums.com/showthread.php?t=31239
... specifically posts 4 and 18.
 
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  • #7
Thanks again Simon for some great information. I skimmed through a bit tonight and will be sure to take a better look at it this week when I have time.
 
  • #8
It's written to be the last word so, of course, it won't be :)
 

FAQ: Question regarding magnetic fields being unable to do work?

1. How can a magnetic field be unable to do work?

A magnetic field is unable to do work because it does not possess any energy. It is simply a force that is exerted on magnetic materials, causing them to move or change direction. In order for work to be done, energy must be transferred, and a magnetic field does not have the ability to transfer energy.

2. Why do we often hear that magnets can do work?

Magnets themselves do not do work, but they can be used in devices such as motors and generators to convert energy from one form to another. In these cases, the magnetic field is used to manipulate the movement of electrons, which ultimately results in work being done.

3. Can a magnetic field ever do work?

In certain situations, a magnetic field can indirectly do work by influencing the movement of charged particles, such as in the case of a particle accelerator. However, the work is actually being done by the particles themselves, not the magnetic field.

4. How is the strength of a magnetic field measured?

The strength of a magnetic field is typically measured in units of tesla (T) or gauss (G). These units represent the strength of the magnetic field at a certain point in space. The strength of a magnetic field can also be measured by the force it exerts on a charged particle or a magnetic material.

5. Can a magnetic field be used to lift objects or perform physical tasks?

No, a magnetic field alone cannot lift objects or perform physical tasks. However, it can be used in conjunction with other forces, such as gravity or electromagnetism, to achieve these tasks. This is commonly seen in devices such as cranes or magnetic levitation trains.

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