Quick question on Newton's third law & energy conservation

AI Thread Summary
In the discussion, the question revolves around the application of Newton's third law and the conservation of energy when a 100 kg astronaut pushes a 100 kg rock in space. The key point is that both the astronaut and the rock would move at 0.707 m/s relative to an observer, resulting in a total kinetic energy of 50 joules, not 100 joules. This conclusion is supported by the principle that energy is conserved in the system. The conversation highlights a common misconception in various sources that suggest both would have speeds of 1 m/s, which would imply a gain of energy. The clarification emphasizes the importance of accurate interpretations of physical laws in educational materials.
DavidDoakes
Messages
3
Reaction score
0
I have a quick question on Newton's third law.

When a 100kg astronaut in space is holding a 100 kg rock and then pushes it away from him with 50 joules of energy (the kinetic energy put into the system) and a second astronaut (observer) is watching, sitting still relatively to the location where the other astronaut was holding the rock and generating the 50 joules before the push, does the observer see the rock float to the left of him with 1 m/s and the astronaut float to the right of him with 1 m/s or does he see the rock float to the left with 0.707 m/s and the astronaut to the right with 0.707 m/s? In other words, is the total kinetic energy he observes equal to 100 joules or 50 joules?
 
Science news on Phys.org
Hi DavidDoakes, welcome to PF!
DavidDoakes said:
pushes it away from him with 50 joules of energy (the kinetic energy put into the system) ... is the total kinetic energy he observes equal to 100 joules or 50 joules?
Energy is conserved. What does that imply for your question?
 
DaleSpam said:
Hi DavidDoakes, welcome to PF!Energy is conserved. What does that imply for your question?

I'd say both the astronaut and rock would have speeds of 0.707 m/s relative to the observer (otherwise you can could catch both the astronaut's and the rock's kinetic energy, transport it to the center of the system and use half of it to repeat the whole thing, gaining 50 joules of free energy every time), but there are so many (popular) sources out there that explain it like they would have speeds of 1 m/s relative to the observer, so I was wondering if I missed something.
 
DavidDoakes said:
I'd say both the astronaut and rock would have speeds of 0.707 m/s relative to the observer (otherwise you can could catch both the astronaut's and the rock's kinetic energy, transport it to the center of the system and use half of it to repeat the whole thing, gaining 50 joules of free energy every time)
You are correct, both in your conclusion and your reasoning.

If you look at a more detailed analysis, suppose the astronaut has an arm length of 1 m and pushes with 50 N force. If the astronaut were pushing on a very massive object that did not displace much then he would travel 1 m during the push and all 50 J would go into his KE. If the astronaut were pushing on a very light object so that he did not displace much then that object would travel 1 m during the push and all 50 J would go into the object. Since the mass is the same as the astronaut, neither of these ideal situations occur, instead both the astronaut and the rock move 0.5 m during the push, so each gets 25 J.
 
Last edited:
DaleSpam said:
You are correct, both in your conclusion and your reasoning.

If you look at a more detailed analysis, suppose the astronaut has an arm length of 1 m and pushes with 50 N force. If the astronaut were pushing on a very massive object that did not displace much then he would travel 1 m during the push and all 50 J would go into his KE. If the astronaut were pushing on a very light object so that he did not displace much then that object would travel 1 m during the push and all 50 J would go into the object. Since the mass is the same as the astronaut, neither of these ideal situations occur, instead both the astronaut and the rock move 0.5 m during the push, so each gets 25 J.

Thank you for clearing this up for me. Doesn't it bother you that so many sources explain this incorrectly (or at least in such a way that it's easy to interpret it incorrectly)?
 
Been around 40 years since I took basic physics in college and while I remember doing some examples of insulation values / energy conduction, I doubt I could to the math now even if I could find the formulas. I have some some corrugated plastic sheet (think of the plastic signs you see on the side of the road) that is used in bee hives. Also have some used in a green house though a bit different in dimensions than this example but the general approach should still apply. Typically, both...
Problem: You’re an Uber driver with a Tesla Model 3. Today’s low: 30F, high: 65F. You want to reach a USD$ profit target in the least number of hours, but your choices could have added cost. Do you preheat the battery only when you are headed to the charging station (to increase the charging rate by warming the battery — however the battery might not be “warm enough” when your reach the charger and thus slower charging rates), or do you always “navigate to the charger” the entire day (which...
Thread 'Is Callen right in claiming dQ=TdS for all quasi-static processes?'
Hello! I am currently reading the second edition of Callen's Thermodynamics and an Introduction to Thermostatistics, and I have a question regarding Callen's definition of quasi-static. On page 96, Callen says: Another way of characterizing Callen's definition is that a process is quasi-static if it traces out a continuous curve in the system's configuration space. So far it's all well and good. A little later, Callen claims that the identification of $$TdS$$ as the heat transfer is only...

Similar threads

Replies
28
Views
4K
Replies
20
Views
2K
Replies
4
Views
2K
Replies
6
Views
2K
Replies
4
Views
9K
Replies
4
Views
3K
Back
Top