Radiation Rate of 0.1m Cube Metal at 200C

AI Thread Summary
To calculate the radiation rate of a 0.1m cube of metal with an emissivity of 0.75 at 200°C, the formula H=AeσT^4 is used, where σ is the Stefan-Boltzmann constant. The area of one face of the cube is 0.01 m², and since a cube has six faces, the total area is 0.06 m². Converting 200°C to Kelvin gives 473K, and substituting these values into the formula results in a radiation rate of 128W, correcting the initial miscalculation of 21.28W. Proper unit conversion and consideration of the cube's total surface area are crucial for accurate results.
Kyle North
Messages
2
Reaction score
0

Homework Statement


At what rate does a 0.1m cube of metal with emissivity e=0.75 radiate energy if it is at a temperature of 200C?

Homework Equations



H=AeσT^4, σ=5.67 x10^-8

The Attempt at a Solution


I found the area of the cute to be A=(0.1m)^2=0.01m, and the turned 200C into 473K, but when I type them all in I get 21.28W and the answer is 128W?
 
Physics news on Phys.org
How many faces does a cube have?
 
6.. thanks!
 
Also, (0.1 m)2 = 0.01 m2 Don't forget to square the units.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Back
Top