Range of a function, very simple & basic question

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The discussion focuses on finding the range of two quadratic functions within specified intervals. For the first function, f(x) = 3x² + 4, the range is determined to be 4 ≤ f(x) ≤ 52 by following a systematic approach. The second function, f(x) = 9 - 2x², initially causes confusion, but it is clarified that the steps taken to find the range are correct, specifically regarding squaring the bounds and reversing inequalities when multiplying by negative numbers. The final steps involve adding constants to complete the range calculation. The conversation emphasizes the importance of following each step carefully to achieve the correct answer.
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Just go through the following problem

Question 1:find the range of the following function
f(x)=3x2+4 for -4≤x≤3

Answer:
rewriting -4≤x≤3
step1. 0≤x2≤16
step2. multiply 3 for the entire step 1.
step4. add 4 for the entire step1.
step5. 4≤f(x)≤52

so the above problem i have understood

now how do i solve the following problem using the same method as above, because the following problem is a bit different from the first one, and i get a reverse answer

Question 2: find the range of the following function
f(x)=9-2x2 for -3≤x≤3

rewriting -3≤x≤3
step 1. 0≤x2≤9 now is this step correct?, i don't think so.
step 2. ?
step 3. ?
step 4. ?

please note: i cannot find the range directly because each step carries marks
 
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The step is correct. .

if you square x<=3 that will give you (x^2 <=9) or (x<0)
if you square x>=-3 that will give you ((x^2 <= 9) or (x>0))

if both are true you just get (x^2 <= 9)
 
sachin_naik04 said:
Just go through the following problem

Question 1:find the range of the following function
f(x)=3x2+4 for -4≤x≤3

Answer:
rewriting -4≤x≤3
step1. 0≤x2≤16
step2. multiply 3 for the entire step 1.
step4. add 4 for the entire step1.
step5. 4≤f(x)≤52

so the above problem i have understood

now how do i solve the following problem using the same method as above, because the following problem is a bit different from the first one, and i get a reverse answer

Question 2: find the range of the following function
f(x)=9-2x2 for -3≤x≤3

rewriting -3≤x≤3
step 1. 0≤x2≤9 now is this step correct?, i don't think so.
Yes, it is correct. Why would you not think so?

step 2. ?
Multiplying each part of the inequality by negative 2 reverses the inequality:
-18\le x^2\le 0
Since you say you got a "reverse answer" that may have been your mistake.

step 3. ?
Add 9 to each part.

step 4. ?
Write down your answer!

please note: i cannot find the range directly because each step carries marks
 
@HallsofIvy

oh thanks a lot, that helped me
 
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