Reflector flux contribution

  • Thread starter Thread starter ameermukhtar
  • Start date Start date
AI Thread Summary
The discussion centers on achieving a neutron flux greater than 5e8 n/sqcm.second in a Beam Shape Assembly (BSA) setup for Boron Neutron Capture Therapy. The setup involves lithium-7 on copper within an iron container in a hydrogen-filled space inside a large beryllium sphere. Participants inquire about the neutron source's activity and the specifics of the neutron production rate, particularly focusing on the flux at the end of cell 7. Clarifications about the dimensions of the beryllium sphere and the target flux are also provided. The goal is to optimize the neutron flux for effective therapy applications.
ameermukhtar
Messages
17
Reaction score
1
Hi
this is the attached file . i want to get the flux at the end of BSA which is cell 7 also the flux of cell 8 is less than 5e8. now my target is to get the flux greater than 5e8. thank you to all
 

Attachments

Engineering news on Phys.org
You have a target of lithium-7 on copper on alumina etc inside an iron container inside a hydrogen filled space in a large beryllium sphere. Is that right?

You want the neutron flux in the beryllium sphere to exceed 5e8 n/sqcm.second? What is the activity of the neutron source?

What does BSA mean please?
 
yes you are right. BSA means " Beam Shape Assembly" . and you are right i want flux 5e8. acutually i am doing Boron neutron capture therapy
 
It might be more normal to simulate for a flux inside some sort of tissue. But you have a sphere of BeO, and you want a flux of 5e8 in it, and it's 6 meters in diameter?

What is the rate of particle production in the source?
 
my neutrons production is in cell 3 and i need the flux at the end of the cell 7
 
Hello, I'm currently trying to compare theoretical results with an MCNP simulation. I'm using two discrete sets of data, intensity (probability) and linear attenuation coefficient, both functions of energy, to produce an attenuated energy spectrum after x-rays have passed through a thin layer of lead. I've been running through the calculations and I'm getting a higher average attenuated energy (~74 keV) than initial average energy (~33 keV). My guess is I'm doing something wrong somewhere...

Similar threads

Back
Top