- #1
Jharr94
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Homework Statement
Ship A is located 3.5 km north and 2.8 km east of ship B. Ship A has a velocity of 22 km/h toward the south and ship B has a velocity of 40 km/h in a direction 37° north of east.
At what time is the separation between the ships least?
Homework Equations
V_ab=V_b-V_a
Where V_ab is the velocity of a with respect to b and V_a or V_b is the velocity of that ship.
The Attempt at a Solution
I'm thinking this part of the problem involves relative motion as well as kinematics, however I can't find out how to get the LEAST distance, the only thing I can think is when the positions are equal, which they should never be however,
I've found the position vector of a with respect to b as:
(2.8-31.95t)i+(3.5-46.07t)j=r_fab (r_fab is final position of a with respect to b)
from this I'm stuck as to where to go, I don't know how to find the LEAST distance between the two, I tried setting the position equations equal to each other( r_b=r_ab) but I can't seem to find answer because there are two different times for the x component and the y component.
Help please, thanks.