- #1
ahsila432
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- Homework Statement
- a ferryboat is travelling in a direction of 28 degrees north of east with a speed of 4.40 m/s relative to the water. A passenger is walking with a velocity of 2.02 m/s due east relative to the boat. What is the magnitude and direction of the velocity of the passenger with respect to the water. Give directional Angle to due east.
- Relevant Equations
- components, velocity equations
So far I have this:
vbwx= 4.40c0s(28) = 3.88496409
vbwy= 4.40sin28 = 2.065674876
vpwx= 4.4ocos28
vpwy= 4.40sin28 +2.02
Find Square root of vpx^2 + vpy^2 = 5.43?
Im confused as to whether we add the 2.02 to the sin28 or the cos28 though, did I do it right? Also, not sure how to find the angle at the end.
vbwx= 4.40c0s(28) = 3.88496409
vbwy= 4.40sin28 = 2.065674876
vpwx= 4.4ocos28
vpwy= 4.40sin28 +2.02
Find Square root of vpx^2 + vpy^2 = 5.43?
Im confused as to whether we add the 2.02 to the sin28 or the cos28 though, did I do it right? Also, not sure how to find the angle at the end.