Relativistic hidden variable quantum mechanics?

In summary, the paper shows that nonlocal hidden variable theories for relativistic quantum mechanics are impossible. Discussions of the assumptions can be found in Laudisa, F. (2014). Against the ‘no-go’philosophy of quantum mechanics. European Journal for Philosophy of Science, 4(1), 1-17. This paper criticizes Gisin's assumptions. Oldofredi, Andrea. "No-Go Theorems and the Foundations of Quantum Physics." Journal for General Philosophy of Science(2018): 1-16. This paper rebuts the criticism of Laudisa. Nikolic
  • #36
Demystifier said:
Physics is not a beauty contest. :biggrin:
Wth regard to theories about unobservable things (as hidden variables are), the only sensible selection criterion is in terms of beauty, simplicity, and the like. This is the content of Ockham's razor.

Thus the physics of hidden variables is a beauty contest.
 
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  • #37
A. Neumaier said:
Thus the physics of hidden variables is a beauty contest.
How about an intuition contest? For me cutoff is indeed ugly, but very intuitive.
 
  • #38
Demystifier said:
The ##(something)## changes the sign precisely when the ##ds^2_{rel}## changes the sign. Therefore it should not be surprising to you that ##0(something)^{-1}=0## precisely when ##ds_{rel}^2=0##, in such a manner that in the appropriate limit ##0^{-1}0\neq 0##.
Is that shown in the paper?
Demystifier said:
I would say that you didn't actually read the paper.
Well, I wrote that in post #18
Demystifier said:
The existence of foliation is not essential for my theory. That indeed is a part of taking 4-dimensional view seriously, because insisting on foliation reflects the desire to have a 3-dimensional view. What is important is that there is no preferred foliation into spacelike hypersurfaces, which reflects relativistic covariance of the theory. What is seen from the picture is that if there is a foliation at all, then it obviously isn't a foliation into spacelike hypersurfaces.
This brings me back to my first question about the initial value problem. You need a hypersurface for the initial conditions. For some equations, if it isn't space-like, it may lead to an ill posed Cauchy problem. There may be no solutions at all. You said that the equations for the other fields are the same, so there is some justification to be done here. Even if you ignore them and only treat particles you still have the quantum potential or the wave function or whatever it is in Bohmian mechanics that guides them. You will have some PDEs and the need of some foliation.
 
  • #39
martinbn said:
Is that shown in the paper?
Not explicitly, it's left as an exercise for the reader, which should be easy for a reader who read the paper carefully. :wink:

martinbn said:
This brings me back to my first question about the initial value problem. You need a hypersurface for the initial conditions. For some equations, if it isn't space-like, it may lead to an ill posed Cauchy problem. There may be no solutions at all. You said that the equations for the other fields are the same, so there is some justification to be done here. Even if you ignore them and only treat particles you still have the quantum potential or the wave function or whatever it is in Bohmian mechanics that guides them. You will have some PDEs and the need of some foliation.
This objection is too general, you don't direct your objection to specific equations in the paper. I could reply by writing down specific equations and explaining why your general objections do not apply in this case, but it wouldn't make much sense if you didn't read the paper.

If you don't have time to read the whole paper, I would suggest you to read only Sec. 3.3 of https://arxiv.org/abs/1002.3226
In this older paper I have not yet been recognizing that ##s## can be interpreted as a generalized proper time, but mathematics relevant to the Cauchy problem is essentially the same.
 
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  • #40
Demystifier said:
How about an intuition contest? For me cutoff is indeed ugly, but very intuitive.
It is not intuitive at all why you assume Lorentz invariance to be violated (through the cutoff), but require it to hold in the first place to define the eligible class of Lagrangians.
 
  • #41
A. Neumaier said:
Wth regard to theories about unobservable things (as hidden variables are),
Is it a formal axiom in BM that hidden variables are unobservable ? Or is it simply the case that we cannot "yet" figure a way to test them (more directly than a EPR experiment, which is pretty much for me a direct observation of non-local hidden variable)
Isn't it the case that in classical QM particle trajectories take an infinite number of "unobservable path (or even virtual)", because as soon as we try to observe them, they "disappear" ?
Is classical "temperature" observable ? Or is it not some kind of useful fiction that we "invented" because we cannot observed the momentum of millions of particles ?

A. Neumaier said:
the only sensible selection criterion is in terms of beauty, simplicity, and the like. This is the content of Ockham's razor.
Which is why my favorite "interpretation" is BM. There is no un-observable infinities or Wolds (if they can at least be defined), nor an unobservable ledger where the "ensemble" of past probabilities are recorded so the next one behave somewhat correctly...

A. Neumaier said:
Thus the physics of hidden variables is a beauty contest.
I agree, that's why I will dig further into your thermal interpretation of QM.
 
  • #42
Boing3000 said:
in classical QM particle trajectories take an infinite number of "unobservable paths''
There is no classical QM. You seem to refer to some version of the Copenhagen interpretation.

Boing3000 said:
Is it a formal axiom in BM that hidden variables are unobservable ?
If they were observable in principle, the predictions would be different from quantum mechanics. But the claim BM makes is that the observable predictions are exactly the same. Thus they have to be unobservable...
 
  • #43
A. Neumaier said:
If they were observable in principle, the predictions would be different from quantum mechanics. But the claim BM makes is that the observable predictions are exactly the same. Thus they have to be unobservable...
Different or just more precise ? As every new theory try to reproduce the previous one "as a limit", I don't understand your logic.
As QM cannot even predict where one photon/electron/whatever will end up on that plate (whatever the number of slits), I always supposed the goal of BM was to be able to predict at least with reasonable precision the destination position/value given that we knew with reasonable precision the hidden variables values
Now if those BM trajectories are totally chaotic (small variation in hidden variable values => huge variation in destination position), then the whole endeavor still seams to me to be more than pointless, because I would understand how nature "implement" itself, using some very simple tricks.
 
  • #44
A. Neumaier said:
It is not intuitive at all why you assume Lorentz invariance to be violated (through the cutoff), but require it to hold in the first place to define the eligible class of Lagrangians.
Cutoff is intuitive, Lorentz invariance is beautiful. In this way, like in a marriage, one retains both, or loses both, depending on whether one is optimist or pessimist. :biggrin:

When I was writing this paper I was an optimist. In the meanwhile I became a pessimist, so now my preferred version of Bohmian mechanics is different, the one in which fundamental Lorentz invariance is completely rejected. In this way the unnatural marriage is divorced, so Bohmian mechanics can be fully intuitive and ugly. :woot:
For more details on the evolution of my thoughts see https://www.physicsforums.com/insights/stopped-worrying-learned-love-orthodox-quantum-mechanics/
 
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  • #45
Demystifier said:
It's a classical apparatus, so this time is described by the standard classical proper time.

This would mean that a classical apparatus cannot follow the spacelike trajectories shown in Fig. 1, correct? Those trajectories can only be followed by the unobservable Bohmian particles?
 
  • #46
PeterDonis said:
This would mean that a classical apparatus cannot follow the spacelike trajectories shown in Fig. 1, correct? Those trajectories can only be followed by the unobservable Bohmian particles?
Yes.
 
  • #47
Demystifier said:
Yes.

So what in your model prevents a classical apparatus from following a spacelike trajectory, if the individual Bohmian particles can?
 
  • #48
Demystifier said:
Not explicitly, it's left as an exercise for the reader, which should be easy for a reader who read the paper carefully.
Well, you have established that I am not a reader of the article. Can the writer supply the proof?
Demystifier said:
This objection is too general, you don't direct your objection to specific equations in the paper. I could reply by writing down specific equations and explaining why your general objections do not apply in this case, but it wouldn't make much sense if you didn't read the paper.
Well, let's say equation ##(94)## or if you prefer ##(99-100)## with the equations for the particles ##(117)##. How do you set up the IVP?
 
  • #49
Boing3000 said:
if those BM trajectories are totally chaotic
They are, so the detailed predictions are untestable. That's the whole point. BM is not supposed to predict in any real sense but to solve the interpretation problem by introducing some sort of reality into the picture.
 
  • #50
Demystifier said:
now my preferred version of Bohmian mechanics is different, the one in which fundamental Lorentz invariance is completely rejected.
But then the problem of how to motivate and explain the Lagrangian of QED, QCD and the standard model, which are all based on Lorentz invariance, becomes even more pressing. Just assuming that there is a miraculous way these appear by coarse graining from some unspecified and unknown noninvariant theory requires a lot of faith, and few would follow your faith.
 
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  • #51
PeterDonis said:
So what in your model prevents a classical apparatus from following a spacelike trajectory, if the individual Bohmian particles can?
A classical apparatus is a macroscopic object, the trajectory of which is defined by the motion of the non-empty wave packet. See Fig. 2 in https://arxiv.org/abs/1309.0400 for an idea how macroscopic trajectory may look very different from the microscopic one.
 
  • #52
A. Neumaier said:
But then the problem of how to motivate and explain the Lagrangian of QED, QCD and the standard model, which are all based on Lorentz invariance, becomes even more pressing. Just assuming that there is a miraculous way these appear by coarse graining from some unspecified and unknown noninvariant theory requires a lot of faith, and few would follow your faith.
"The reasonable man adapts himself to the world; the unreasonable one persists in trying to adapt the world to himself. Therefore all progress depends on the unreasonable man."
- George Bernard Shaw
 
  • #53
Demystifier said:
"The reasonable man adapts himself to the world; the unreasonable one persists in trying to adapt the world to himself. Therefore all progress depends on the unreasonable man."
- George Bernard Shaw
Well, Shaw didn't achieve anything in physics. Progress in physics depends on finding something adapted both to the world and to one's vision! This characterized the work of Planck, Einstein, Heisenberg, Dirac, Feynman ...
 
  • #54
martinbn said:
Well, let's say equation ##(94)## or if you prefer ##(99-100)## with the equations for the particles ##(117)##. How do you set up the IVP?
One first writes down the general solution of (94), parametrized by an infinite number of free constants. Then one picks a particular solution by picking some specific values of those constants. In this way (94) is solved without choosing an initial value. Finally, one solves (117) by an initial condition at, say, ##s=0##.
 
  • #55
A. Neumaier said:
Well, Shaw didn't achieve anything in physics. Progress in physics depends on finding something adapted both to the world and to one's vision! This characterized the work of Planck, Einstein, Heisenberg, Dirac, Feynman ...
How about string theorists like Maldacena, Witten, etc? Would you say that they achieved something in physics?
 
  • #56
martinbn said:
Can the writer supply the proof?
He can, which doesn't mean that he will. :-p
You have to be a better motivator. You have to say something like "Wow, you explained that so well, it would be great if you could just fill this little detail, so that my understanding of your great ideas can be complete." :biggrin:

But I am in a good mood these days, so I will give you a sketch of the proof for ##n=1##. Suppose that ##V^{\mu}V_{\mu}=0##, but ##V^{\mu}\neq 0## and ##V^{\mu}\neq \infty##. Then
$$\frac{dX^{\mu}}{ds}=V^{\mu}\neq 0, \infty \;\;\;\; (1)$$
Therefore on a line segment on which ##dX^{\mu}\neq 0## we have ##dX^{\mu}dX_{\mu}=0##, but (1) implies that ##ds\neq 0##. ##\Box##

If you don't accept a proof using infinitesimals, I live it to you to reformulate this in the ##\epsilon##-##\delta## language or in an integral form.
 
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  • #57
Demystifier said:
How about string theorists like Maldacena, Witten, etc? Would you say that they achieved something in physics?
The future will tell about the contribution of string theory to physics.

But Witten also contributed to ordinary QFT and to pure mathematics. In mathematics he obtained the fields medal, at the time the highest distinction.
 
  • #58
A. Neumaier said:
The future will tell about the contribution of string theory to physics.
Likewise the future will tell whether Lorentz invariance is only emergent at a coarse grained level.
 
  • #59
Demystifier said:
Likewise the future will tell whether Lorentz invariance is only emergent at a coarse grained level.
But we are discussing the present state of affairs.
 
  • #60
Demystifier said:
One first writes down the general solution of (94), parametrized by an infinite number of free constants. Then one picks a particular solution by picking some specific values of those constants. In this way (94) is solved without choosing an initial value. Finally, one solves (117) by an initial condition at, say, ##s=0##.
It is still not clear to me. What do you mean by the general solution with infinite number of constants? And how do you pick their values? What information is given?

Here is a simple example. Take the usual wave equation in ##1+1## dimensions. It has a general solution ##u(x,t)=f(x-ct)+g(x+ct)## for arbitrary functions ##f## and ##g##. How do you pick your solution? And what happens in higher dimensions, what is the general solution?
 
  • #61
A. Neumaier said:
But we are discussing the present state of affairs.
You are the one who first mentioned future in relation to the value of string theory.
 
  • #62
Demystifier said:
You are the one who first mentioned future in relation to the value of string theory.
Only because you asked a question unrelated to the thread.
 
  • #63
Demystifier said:
He can, which doesn't mean that he will. :-p
You have to be a better motivator. You have to say something like "Wow, you explained that so well, it would be great if you could just fill this little detail, so that my understanding of your great ideas can be complete." :biggrin:

But I am in a good mood these days, so I will give you a sketch of the proof for ##n=1##. Suppose that ##V^{\mu}V_{\mu}=0##, but ##V^{\mu}\neq 0## and ##V^{\mu}\neq \infty##. Then
$$\frac{dX^{\mu}}{ds}=V^{\mu}\neq 0, \infty \;\;\;\; (1)$$
Therefore on a line segment on which ##dX^{\mu}\neq 0## we have ##dX^{\mu}dX_{\mu}=0##, but (1) implies that ##ds\neq 0##. ##\Box##

If you don't accept a proof using infinitesimals, I live it to you to reformulate this in the ##\epsilon##-##\delta## language or in an integral form.
Well, it doesn't imply ##ds\neq 0##, it implies ##ds=\frac00##.

But you are just assuming something about the world line. The claim is that the dynamics imply that the ##(something)## has the correct sign or order of vanishing. I don't see even a hint of that, let alone a sketch of proof.
 
  • #64
martinbn said:
It is still not clear to me. What do you mean by the general solution with infinite number of constants? And how do you pick their values? What information is given?

Here is a simple example. Take the usual wave equation in ##1+1## dimensions. It has a general solution ##u(x,t)=f(x-ct)+g(x+ct)## for arbitrary functions ##f## and ##g##. How do you pick your solution? And what happens in higher dimensions, what is the general solution?
Now you ask me questions about standard theory of partial differential equations. I think it's not directly relevant to my relativistic hidden variable theory.
 
  • #65
Demystifier said:
Now you ask me questions about standard theory of partial differential equations. I think it's not directly relevant to my relativistic hidden variable theory.
Ok, answer the same question for equations ##(94)##. What is the general solution and how do you pick the constants? What information is given so that you can determine those constants.
 
  • #66
martinbn said:
Well, it doesn't imply ##ds\neq 0##, it implies ##ds=\frac00##.
Sorry, but you are wrong.
 
  • #67
martinbn said:
Ok, answer the same question for equations ##(94)##. What is the general solution and how do you pick the constants? What information is given so that you can determine those constants.
Let me first make one thing clear. Do you ask because you want to learn something, or do you ask because you want to find my error? I have the feeling that you only want the latter, so you ask nitpicking questions, which are actually easy to me, but I find them pretty much irrelevant.
 
  • #68
Demystifier said:
Sorry, but you are wrong.
Don't you have ##V^{\mu}V_{\mu}## in the denominator?
 
  • #69
Demystifier said:
Let me first make one thing clear. Do you ask because you want to learn something, or do you ask because you want to find my error? I have the feeling that you only want the latter, so you ask nitpicking questions, which are actually easy to me, but I find them pretty much irrelevant.
I don't know if you have an error. I just want to understand the statements, because they make no sense to me. But you don't have to waste time with this, it isn't important.
 
  • #70
martinbn said:
Don't you have ##V^{\mu}V_{\mu}## in the denominator?
From equation (1) above one has (no sum over ##\mu##)
$$ds=\frac{dX^{\mu}}{V^{\mu}}=\frac{non zero}{non zero}$$
 

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