Rest energy and Kinetic Energy of a Photon - velocity?

AI Thread Summary
The discussion centers on a physics problem regarding the relationship between a photon's kinetic energy and its rest energy. The correct answer for the velocity of a photon, when its kinetic energy equals its rest energy, is expressed as sqrt(3)/2 x c. Participants clarify that the term "kinetic energy" in the context of relativity refers to the total energy minus the rest energy. The confusion arises from the traditional kinetic energy equation, which does not apply to photons since they have no rest mass. Ultimately, understanding the correct framework for energy in relativity resolves the initial misunderstanding.
max8404
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Homework Statement



Thanks for everyone that helped me with the physics questions! I had my physics 2 final today and got a 94! There was a question that I could not figure out for a long time. It goes like this.

What would the velocity of the photon be if the Kinetic energy of the photon equals the rest energy of the photon? Express v in terms of c and anything else. Luckily, the question was a multiple choice, and the correct answer (which I guessed) was sqrt(3)/2 x c

I still cannot figure out why this is true.


Homework Equations



K=1/2mv^2 --> I assume this is the right equation to use...
Er=mc^2

The Attempt at a Solution



Equaling the two would give you:

1/2mv^2=mc^2

v^2=2c^2
v=sqrt(2) x c

This is obviously not true since you can't go faster than the speed of light. Can someone explain to me how the answer is sqrt(3)/2 x c and why I am getting this thing wrong? Am I using the right Kinetic Energy equation??

Thanks!
 
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congratulations!

Hi max8404! Many congratulations! :biggrin:
max8404 said:
What would the velocity of the photon be if the Kinetic energy of the photon equals the rest energy of the photon? Express v in terms of c and anything else. Luckily, the question was a multiple choice, and the correct answer (which I guessed) was sqrt(3)/2 x c

Homework Equations



K=1/2mv^2 --> I assume this is the right equation to use...
… why I am getting this thing wrong? Am I using the right Kinetic Energy equation??

oooh, I wish examiners wouldn't use "kinetic energy" in relativity :cry:

they just mean total energy minus rest energy :rolleyes:

so 2m = m/√(1 - v2/c2), so 1 - v2/c2 = 1/4 :wink:
 


tiny-tim said:
Hi max8404! Many congratulations! :biggrin:


oooh, I wish examiners wouldn't use "kinetic energy" in relativity :cry:

they just mean total energy minus rest energy :rolleyes:

so 2m = m/√(1 - v2/c2), so 1 - v2/c2 = 1/4 :wink:

Hey Tiny Tim, thanks for your response, but I doon't quite get it. I understand the equation,
E=KE+mc^2, but in this case, what would E be? Or am I once again looking at it the wrong way?

Thanks!
 
E is the total energy (or relativistic energy), mc2/√(1 - v2/c2) :smile:
 
tiny-tim said:
E is the total energy (or relativistic energy), mc2/√(1 - v2/c2) :smile:

duh. thanks a lot! I got it now! :)
 
I have a big problem with a photon's velocity being less than c.
 
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