Return to the center of the Earth

In summary, "Return to the Center of the Earth" is a science fiction adventure that follows a group of explorers who embark on a journey to the Earth's core. They encounter various challenges, including extreme environments and prehistoric creatures, while uncovering ancient mysteries. The narrative combines elements of action, discovery, and the exploration of human resilience as the characters strive to survive and understand the hidden depths of the planet.
  • #1
ActaPhysica
4
0
TL;DR Summary
The usual approach for solving for the time it takes to fall to the center of the earth neglects air resistance & uses Hooke's Law. But if you solve it "the hard way"...
The usual approach for solving for the time it takes to fall to the center of the earth neglects air resistance & uses Hooke's Law. But if you solve it "the hard way"...
Gme*m/r^2 = ma
me = 4/3 rho pi r^3
G * 4/3 rho pi r = a
separate variables, integrate twice
r*Ln(r) - r = 2/3 G rho pi t^2
The lower limit of integration (0) has Ln(0) getting large and negative much more slowly than r going to 0, so there's no problem here.
But, this answer gives a very large time. What am I doing wrong?
 
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  • #2
ActaPhysica said:
G * 4/3 rho pi r = a
This is your ”Hooke’s law”. You are not integrating correctly.
 
  • #3
It's not my Hooke's Law it's Hooke's Law :)
Can you point out my mistake?
 
  • #4
ActaPhysica said:
It's not my Hooke's Law it's Hooke's Law :)
Can you point out my mistake?
The point is: It is not Hooke’s law. Hooke’s law relates to the elastic force in a spring or material. It is not simply any linear force.

I already pointed out your mistake: You did not integrate correctly. If you want more detail than that you need to provide your actual computation because your current one is only saying ”integration gives” and then a wrong statement.
 
  • #5
Well if you integrate 1/r that gives Ln(r)
And if you integrate Ln(r) it gives rLn(r) - r
The other side is pretty straightforward.
 
  • #6
ActaPhysica said:
Well if you integrate 1/r that gives Ln(r)
And if you integrate Ln(r) it gives rLn(r) - r
The other side is pretty straightforward.
But that is the wrong thing to integrate. So again please show your actual work step by step. If you stubbornly refuse to provide this you are making it impossible to help you.
 
  • #7
G * 4/3 rho pi r = a = d^2r / dt^2
4/3*G*rho*pi dt^2 = 1/r d^2r
4/3*G*rho*pi *t dt = Ln (r) dr
4/3*G*rho*pi * t^2/2 = r*Ln(r) - r
Is this detailed enough?
 
Last edited:
  • #8
ActaPhysica said:
TL;DR Summary: The usual approach for solving for the time it takes to fall to the center of the earth neglects air resistance & uses Hooke's Law. But if you solve it "the hard way"...

The usual approach for solving for the time it takes to fall to the center of the earth neglects air resistance & uses Hooke's Law. But if you solve it "the hard way"...
Gme*m/r^2 = ma
me = 4/3 rho pi r^3
G * 4/3 rho pi r = a
separate variables, integrate twice
r*Ln(r) - r = 2/3 G rho pi t^2
The lower limit of integration (0) has Ln(0) getting large and negative much more slowly than r going to 0, so there's no problem here.
But, this answer gives a very large time. What am I doing wrong?
What is your definition for the variable, me ?,
 
  • #9
ActaPhysica said:
What am I doing wrong?
  1. Try to use LaTeX to make your formulas more readable. For example, your expression for the interior-mass ##m_e## of the earth between its center and the radius ##r(t)## can be written:$$m_{e}(t)=\frac{4\pi}{3}\rho\,r^{3}(t)\tag{1}$$where ##\rho## is the density of the earth (assumed constant).
  2. You wrote the following differential-equation based on Newton's Second Law:$$\frac{4\pi}{3}Gmr(t)=m\ddot{r}(t)\tag{2}$$Think about the sign of the force here. Is gravity repulsive or attractive?
  3. You can't solve a second-order differential equation like (2) by performing two ordinary integrations over each variable ##r## and ##t## separately. Instead, find its solution the same way you'd solve the simple-harmonic-oscillator equation:$$\ddot{x}(t)+\omega^{2}x(t)=0\tag{3}$$
 
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  • #10
ActaPhysica said:
G * 4/3 rho pi r = a = d^2r / dt^2
4/3*G*rho*pi dt^2 = 1/r d^2r
4/3*G*rho*pi *t dt = Ln (r) dr
4/3*G*rho*pi * t^2/2 = r*Ln(r) - r
Is this detailed enough?
You can't seperate variables this way (with second derivatives).
 
  • #11
ActaPhysica said:
G * 4/3 rho pi r = a = d^2r / dt^2
4/3*G*rho*pi dt^2 = 1/r d^2r
4/3*G*rho*pi *t dt = Ln (r) dr
4/3*G*rho*pi * t^2/2 = r*Ln(r) - r
Is this detailed enough?
That’s simply not how separation of variables work with second derivatives. Your separation of variables is incorrect, leading to an incorrect result.
 

FAQ: Return to the center of the Earth

What is "Return to the Center of the Earth" about?

"Return to the Center of the Earth" is a fictional adventure story that follows a group of explorers who embark on a journey to the Earth's core, inspired by the classic novel "Journey to the Center of the Earth" by Jules Verne. The narrative typically involves themes of discovery, survival, and the exploration of unknown realms beneath the Earth's surface.

Is "Return to the Center of the Earth" based on real science?

While the story may incorporate some scientific concepts, it is primarily a work of fiction. The actual conditions and materials found within the Earth's interior are not accurately depicted, as the extreme heat and pressure make it impossible for humans to explore the core directly.

What are the main challenges faced by the characters in the story?

The characters in "Return to the Center of the Earth" often face numerous challenges, including navigating treacherous terrain, dealing with extreme temperatures, encountering unusual creatures, and overcoming interpersonal conflicts. These obstacles test their resolve and ingenuity as they strive to reach their destination.

Are there any adaptations of "Return to the Center of the Earth"?

Yes, "Return to the Center of the Earth" has inspired various adaptations in film, television, and literature. These adaptations may take creative liberties with the original story, introducing new characters and plotlines while retaining the core theme of exploring the Earth's depths.

What themes are explored in "Return to the Center of the Earth"?

The story explores themes such as curiosity and the human spirit of exploration, the clash between science and myth, the importance of teamwork and friendship, and the consequences of human actions on the environment. These themes resonate with audiences and provoke thought about our relationship with the planet.

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