RLC Circuit Homework - Solving 3rd Part with 2nd Order DE

In summary, the conversation involves solving a problem with three parts, with the third part involving the use of a 2nd order differential equation and a particular integral. The method used is to differentiate and substitute the particular integral to find constants, but there is a known trick to simplify the process by finding the imaginary part of V_0 exp(iwt). This simplifies the problem and makes it more manageable.
  • #1
bigevil
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Homework Statement



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The Attempt at a Solution



Ok, first part, no problem, second part (steady state), solved in another thread. Both are pretty tedious, but doable.

However, I am quite stumped by the third part of this problem (V = V_o sin wt) .

The second part of the problem requires me to use a 2nd order differential equation (y'' + ay' + b = 0), and the solutions of the auxiliary equation can be saved for the third part.

For the third part, I choose a particular integral y = A sin wt + B cos wt. The last part arises essentially because the GS of the third part is y = exponent + exponent + A sin wt + B cos wt, and the first two terms become 0 when t is large. Then I can reexpress A sin wt + B cos wt into the form required.

I have just tried to go about the third part the standard way (differentiating and substituting the particular integral to find A and B, and then substituting again to find the constants in the complementary function), but it is extremely tedious (one page working just to find and simplify A or B) and I hope there is a shorter solution.
 
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  • #2
There is a well-known trick. V_0 sin wt is the imaginary part of V_0 exp(iwt).
i.e. V_0 sin wt = Im( V_0 exp(iwt) )

Also, since the coefficients of the differential equation are real, real and imaginary part of the left and the right hand side of the equation behaves independently. Hence, the solution you are looking for is the imaginary part of the solution for V_0 exp(iwt).

Try to solve for V_0 exp(iwt). It simplifies the problem considerably.
 

FAQ: RLC Circuit Homework - Solving 3rd Part with 2nd Order DE

What is an RLC circuit?

An RLC circuit is an electrical circuit that contains a resistor (R), inductor (L), and capacitor (C) connected in series or parallel. These components determine the behavior of the circuit and how it responds to changes in voltage and current.

What is a 3rd part in a 2nd order differential equation?

In an RLC circuit, the 3rd part refers to the external voltage or current source that is applied to the circuit. This external source can affect the behavior of the circuit and must be taken into account when solving for the circuit's response.

How do I solve an RLC circuit using a 2nd order differential equation?

To solve an RLC circuit using a 2nd order differential equation, you will need to use Kirchhoff's laws to write out the equations for the circuit. Then, you can use techniques such as substitution or Laplace transforms to solve for the voltage or current in the circuit.

What does the solution to a 2nd order differential equation represent in an RLC circuit?

The solution to a 2nd order differential equation in an RLC circuit represents the behavior of the circuit over time. It shows how the voltage or current in the circuit changes in response to the external source and the properties of the circuit components.

Can I use a calculator to solve an RLC circuit with a 2nd order differential equation?

Yes, you can use a calculator to solve an RLC circuit with a 2nd order differential equation. However, you will need to have a good understanding of the mathematical concepts and techniques involved in order to accurately input the equations and interpret the results.

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