Rotational motion and tangential speed?

AI Thread Summary
To determine the maximum speed of a 919 kg rollercoaster on a circular track with a diameter of 16.21 m without leaving the track, the balance of forces must be analyzed. A free-body diagram illustrates that the gravitational force must equal the required centripetal force at the highest point of the track. The centripetal force is dependent on the tangential velocity, which can be calculated using the formula F=ma. The discussion emphasizes that while gravity varies with the angle, it can be simplified for introductory physics problems. Understanding the relationship between gravitational force and centripetal acceleration is crucial for solving this problem.
yramos9
Messages
3
Reaction score
0

Homework Statement


A 919 kg rollercoaster is about to go up a hill that acts as the top of a circle 16.21m in diameter. What is the fastest that car can move (in m/s) without leaving a track?
known:
mass: 919 kg
diameter: 16.21
radius: 8.105

Homework Equations


Vt=r\omega
\omega=\theta/time

The Attempt at a Solution


i have no idea how to work this out without knowing the time or speed or somekind of time measurement. Is there another way to solve this?
 
Physics news on Phys.org
centrifugal force

force balance

free body diagram
 
huh??
 
Draw a free-body diagram of the cart with centrifugal force pulling it up and gravity pulling it down. The sum of the forces on the cart should be zero in the radial direction (since that's the direction for which you don't want motion). Centrifugal force should be a function of tangential velocity, which is the velocity in question.

What level of physics is this? Gravity would realistically be a function of the angle about the center of the circle and only be exactly g when the cart is exactly on the tip of the half-circle. But you could probably neglect this if it's an introductory physics course.
 
this is 11th grage physics pre-ap.. i don't think I've learned what youre trying to teach me.
 
When gravity can provide the centripetal acceleration required to keep the roller coaster on the track, the coaster doesn't fly off. Otherwise, it does. When does gravity exactly equal the required centripetal force? (Hint: F=ma)
 
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...

Similar threads

Back
Top