Scholarpedia article on Bell's Theorem

In summary, the article is a biased overview of the many criticisms of Bell's theorem and does not provide an unbiased perspective.
  • #106
lugita15 said:
At least this part IS extreme skepticism. I thought your (fringe) point of view was that any local hidden variable theory WOULD satisfy a Bell inequality, and thus would contradict QM in principle, but that this inequality would be absolutely untestable experimentally because you can't measure three polarization attributes of one entangled pair. (I'm not agreeing with your point, just saying what I thought your point was.)
I have carefully explained to you previously why experiments violated the inequalities. You did not say if you disagreed with anything in my explanation. You never asked me for the reason why QM violates the inequality, and it has come up in this thread that the reasons are not very different. So what exactly is suprising to you?

I will ask you the same questions I asked ttn:
- Are the 4 terms in the CHSH independent of each other or are they cyclically dependent as I explained?
- Are the 4 terms calculated from QM cyclically dependent on each other or are they independent?
Very simple questions to answer, but the answers begin undoing the brainwashing that has gone on.

But now are you saying that in addition to all that, you're even skeptical about whether this untestable Bell inequality contradicts QM at all, even theoretically?
I also gave a theoretical calculation that violated the inequality. What were you expecting, all that is required is for the assumptions used to derive the inequality to fail in the calculation (whether theoretical or not does not matter).

It is only extreme skepticism to you if you swallow wholesale all the falsehood that is fed to you. I thought for a while that you showed some sound reasoning abilities. If that is still the case, I suggest you write down a list of all the assumptions you think went into the conclusion of non-locality. Including all the hidden ones we have exposed in this thread and at the end explain to yourself, why you are justified in crossing out all of them except the non-locality condition. And don't just cross it out because famous people say it, or because it is popular, because that will not be sound reasoning.
 
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  • #107
Here is another example, based on the case which Boole actually considered. For this case the Bell-like inequality proposed by Legget and Garg is used. The point is that certain assumptions are made about the data when deriving the inequalities, that must be valid in the data-taking process.

Consider a certain disease that strikes persons in different ways depending on circumstances. Assume that we deal with sets of patients born in Africa, Asia and Europe (denoted a,b,c). Assume further that doctors in three cities Lyon, Paris, and Lille (denoted 1,2,3) are are assembling information about the disease. The doctors perform their investigations on randomly chosen but identical days (n) for all three where n = 1,2,3,...,N for a total of N days. The patients are denoted Alo(n) where l is the city, o is the birthplace and n is the day. Each patient is then given a diagnosis of A = +1/-1 based on presence or absence of the disease. So if a patient from Europe examined in Lille on the 10th day of the study was negative, A3c(10) = -1.

According to the Bell-type Leggett-Garg inequality

Aa(.)Ab(.) + Aa(.)Ac(.) + Ab(.)Ac(.) >= -1

In the case under consideration, our doctors can combine their results as follows

A1a(n)A2b(n) + A1a(n)A3c(n) + A2b(n)A3c(n)

It can easily be verified that by combining any possible diagnosis results, the Legett-Garg inequalitiy will not be violated as the result of the above expression will always be >= -1, so long as the cyclicity (XY+XZ+YZ) is maintained. Therefore the average result will also satisfy that inequality and we can therefore drop the indices and write the inequality only based on place of origin as follows:

<AaAb> + <AaAc> + <AbAc> >= -1

Now consider a variation of the study in which only two doctors perform the investigation. The doctor in Lille examines only patients of type (a) and (b) and the doctor in Lyon examines only patients of type (b) and (c). Note that patients of type (b) are examined twice as much. The doctors not knowing, or having any reason to suspect that the date or location of examinations has any influence decide to designate their patients only based on place of origin.

After numerous examinations they combine their results and find that

<AaAb> + <AaAc> + <AbAc> = -3

They also find that the single outcomes Aa, Ab, Ac, appear randomly distributed around +1/-1 and they are completely baffled. How can single outcomes be completely random while the products are not random. After lengthy discussions they conclude that there must be superluminal influence between the two cities.

But there are other more reasonable reasons. Note that by measuring in only two citites they have removed the cyclicity intended in the original inequality. It can easily be verified that the following scenario will result in what they observed:

- on even dates Aa = +1 and Ac = -1 in both cities while Ab = +1 in Lille and Ab = -1 in Lyon
- on odd days all signs are reversed

In the above case
<A1aA2b> + <A1aA2c> + <A1bA2c> >= -3
which is consistent with what they saw. Note that this equation does NOT maintain the cyclicity (XY+XZ+YZ) of the original inequality for the situation in which only two cities are considered and one group of patients is measured more than once. But by droping the indices for the cities, it gives the false impression that the cyclicity is maintained.

The reason for the discrepancy is that the data is not indexed properly in order to provide a data structure that is consistent with the inequalities as derived.Specifically, the inequalities require cyclicity in the data and since experimenters can not possibly know all the factors in play in order to know how to index the data to preserve the cyclicity, it is unreasonable to expect their data to match the inequalities.

For a fuller treatment of this example, see Hess et al, Possible experience: From Boole to Bell. EPL. 87, No 6, 60007(1-6) (2009) cited at the beginning of this thread.

The key word is "cyclicity" here. Now let's look at various inequalities:

Bell's equation (15) in his original paper:
1 + P(b,c) >= | P(a,b) - P(a,c)|
a,b, c each occur in two of the three terms. Each time together with a different partner. However in actual experiments, the (b,c) pair is analyzed at a different time from the (a,b) pair so the bs are not the same. Just because the experimenter sets a macroscopic angle does not mean that the complete microscopic state of the instrument, which he has no control over is in the same state.

CHSH:
|q(d1,y2) - q(a1,y2)| + |q(d1,b2)+q(a1,b2)| <= 2
d1, y2, a1, b2 each occur in two of the four terms. Same argument above applies.

Leggett-Garg:
<Aa(.)Ab(.)> + <Aa(.)Ac(.)> + <Ab(.)Ac(.)> >= -1
 
  • #108
Gordon Watson said:
Some minor points include: the need for much better editing; to wit, the removal of repetition and the correction of typos; the re-location of much material to appendices; etc.

I don't know of any typos (feel free to point them out and we'll fix them), but I am definitely sympathetic to the complaint that the article is too long and in some ways too technical. On the other hand, there is nothing else even nearly as systematic as it out there, so it's good that it exists. But back on the first hand, just because it's good an article like this exists, doesn't mean it should exist as an encyclopedia entry. But hey.

The bias of the authors should be made clear to the reader; bias (imho) being a crucial consideration when it comes to proposed review articles on subjects which are still controversial; the bias in the article tending to the Bohmian (given the assumptions)?

As I have already said, I'm not so sympathetic here. Let's talk first about whether what's in the article is true or not. If it is, then we should be praised for being "biased" in this way, and you can save the complaining for all the other articles that are biased toward false views. On the other hand, if the article is fundamentally wrong, then you might as well just criticize it for that. Either way, the whole issue of "bias" seems like barking up the wrong tree.


Could you therefore please advise the general tenor of each author's physical beliefs and conceptualisations; e.g., Bohmian, MWI, CI, etc?

I think it would be fair to say that we all deeply appreciate the superiority of Bohmian Mechanics over other extant theories (with the exception of GRW type spontaneous collapse theories, which we also appreciate very much).

Incidentally, the same was true for John Bell. And anybody reading this who is surprised to learn that Bell was a Bohmian needs to quit reading biased secondary literature, and read some actual Bell.
 
  • #109
billschnieder said:
I don't recall using the word determinism. All I stated was the obvious fact, acknowledged by Bell in is first equation, that a given outcome for one particular particle is a function of the instrument setting and the specific lambda which is in play during the measurement of that one particle. ie A(a, λ) = ±1.

I thought you were talking about the derivation of the CHHS inequality in our paper. The A's there indeed refer to the outcomes of the measurements but there are no *functions* A(a,λ). That implies determinism -- if you specify the λ and the setting, the outcome is determined. We deliberately avoid making such an assumption in that section.



But it is not sufficient to just "say" it, you have to demonstrate what exactly you mean by "no conspiracy" and hopefully this exercise is bringing out the fact that your "no-conspiracy" assumption is simply the assumption that the probability distribution of the λs actually realized in each run of the experiment are exactly identical to each other. This is an unreasonable assumption which can and is in fact violated in many cases where no conspiracy is in play.

What's an example of a situation where it is violated? I mean, in a real scientific experiment where the experimenters deliberately attempt to avoid any correlation between some "random" setting and some other factor.




You misunderstand. It is up to you to complete your proof before you make extra-ordinary claims that locality is refuted. As you now admit, no experimenter can ever be sure that the same distribution of λ applies to all the terms they calculated. If that is the basis on which you reject locality, then it is indeed a weak basis.

Yes, it's clear we disagree about the reasonableness of this premise.
 
  • #110
DrChinese said:
I told you that your inference is wrong, and that is because there are explicit models that are non-realistic but local and they feature perfect correlations. For example:

http://arxiv.org/abs/0903.2642

Relational Blockworld: Towards a Discrete Graph Theoretic Foundation of
Quantum Mechanics
W.M. Stuckey, Timothy McDevitt and Michael Silberstein
This approach is similar to the Rovelli relational interpretation of QM. Travis et al discuss relational approaches in their paper and admit that such approaches could potentially be fruitful.
 
  • #111
billschnieder said:
Bell's equation (15) in his original paper:
1 + P(b,c) >= | P(a,b) - P(a,c)|
a,b, c each occur in two of the three terms. Each time together with a different partner. However in actual experiments, the (b,c) pair is analyzed at a different time from the (a,b) pair so the bs are not the same. Just because the experimenter sets a macroscopic angle does not mean that the complete microscopic state of the instrument, which he has no control over is in the same state.

I still can't understand you at all. Where in the world did you get the idea that Bell assumes that the "complete microscopic state" is the same, just because the angle is set the same? Nobody ever made that assumption. Not Bell, not us in the article, not anybody. It doesn't even make any sense. Yet you keep going on as if this is being tacitly assumed.

The point, yet again, is that the *distribution* of these λs is assumed to be the same for the (a,b) type runs, as it is for the (b,c) type runs, etc. There is no assumption, and no need for any assumption, about the actual realized λs always being the same for a certain type of run, that the λs should come in exactly the same order for the different runs, or anything remotely like that.
 
  • #112
ttn said:
I don't know of any typos (feel free to point them out and we'll fix them), but I am definitely sympathetic to the complaint that the article is too long and in some ways too technical. On the other hand, there is nothing else even nearly as systematic as it out there, so it's good that it exists. But back on the first hand, just because it's good an article like this exists, doesn't mean it should exist as an encyclopedia entry. But hey.

Sure!

TYPOS, imho; though (granted) some may be a matter of style or for mathematical clarity in the text:

p.5 has "(anti-)correlations" split badly over two lines.

Throughout: Search for space+comma, space+fullstop, space+colon to find incorrect punctuation-spacings.

The 2nd Referee's Report needs editing beyond the above!
ttn said:
As I have already said, I'm not so sympathetic here. Let's talk first about whether what's in the article is true or not. If it is, then we should be praised for being "biased" in this way, and you can save the complaining for all the other articles that are biased toward false views. On the other hand, if the article is fundamentally wrong, then you might as well just criticize it for that. Either way, the whole issue of "bias" seems like barking up the wrong tree.

Well, for me, its a question of style and emphasis. Your definition of "non-local" gave the game away!

And to say this (too), foot of p.2: "But without any such interaction, the ONLY way to ensure perfect anti-correlation between results on the 2 sides is to have each particle carry a pre-existing determinate value ..., for spin along the z-axis." (My emphasis.)

AND that's a pre-existing infinity of values for such believers, right?

For me: Since the particles are unpolarised (per Bell), conservation of angular momentum (and the dynamics of quantum-style spinning-tops) keeps me away from such travisties: :=))

Also: For me, the probability of any two lambda-pairs being the same is zero? Lambda-pairs being drawn from an infinite set of pairs; triples; etc.

ttn said:
I think it would be fair to say that we all deeply appreciate the superiority of Bohmian Mechanics over other extant theories (with the exception of GRW type spontaneous collapse theories, which we also appreciate very much).

Incidentally, the same was true for John Bell. And anybody reading this who is surprised to learn that Bell was a Bohmian needs to quit reading biased secondary literature, and read some actual Bell.

I very much appreciate David Bohm as a person and a physicist; John Bell too; and you! (It's just that I don't do 'weird' very well.)

PS: I look forward to your comments re the "classical challenge".

Regards,

Gordon
..
 
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  • #113
Gordon Watson said:
Well, for me, its a question of style and emphasis. Your definition of "non-local" gave the game away!

I don't know what that is supposed to mean. If anybody has an alternative superior definition of "locality" to propose, I'm all ears.
And to say this (too), foot of p.2: "But without any such interaction, the ONLY way to ensure perfect anti-correlation between results on the 2 sides is to have each particle carry a pre-existing determinate value ..., for spin along the z-axis." (My emphasis.)

AND that's a pre-existing infinity of values for such believers, right?

Yes, the argument establishes that the perfect correlations (along an infinity of possible directions) require an infinity of pre-existing values -- if one assumes locality.
For me: Since the particles are unpolarised (per Bell), conservation of angular momentum (and the dynamics of quantum-style spinning-tops) keeps me away from such travisties: :=))

I don't understand. It's not quite right to say the particles are unpolarized. They're in an entangled superposition wrt polarization. Are you saying the statistics can be explained by a local hidden variable theory? That's certainly wrong.

Incidentally, my middle name is "ty" so your pun is quite familiar!
PS: I look forward to your comments re the "classical challenge".

I looked at it briefly. I don't want to get sucked into a whole 'nuther thread. But it seems like your "challenge" involves asking people to calculate what the correlations will be like if the two photons are each in some polarization eigenstates (no entanglement). Of course the correlations will not violate any Bell/CHHS inequality in that case. If you think they do or might, you haven't understood the theorem at all. Also, in general, and returning the favor of your comments about they style of our article, I don't particularly like the style of posing "challenges" with some mysterious "gotcha" obviously waiting in the wings. If you think you've worked out a counterexample to Bell's theorem (which of course is preposterous, but nevermind that for now) then just put it out there and people will look at it and comment. Don't try to make us do your work for you.
 
  • #114
ttn said:
I thought you were talking about the derivation of the CHHS inequality in our paper. The A's there indeed refer to the outcomes of the measurements but there are no *functions* A(a,λ).
This deviates from Bell's view and contradicts what you actually say in the paper:

More precisely, locality requires that some set of data λ — made available to both systems, say, by a common source16 — must fully account for the dependence between A1 and A2 ; in other words, the randomness that generates A1 out of the parameter α1 and the data codified by λ must be independent of the randomness that generates A2 out of the parameter α2 and λ .

Aren't you saying in effect that A1 = func(α1, λ), and A2 = func(α2, λ)? Just because you mention it in words does not mean you do not have functions. The randomness you talk about, which is introduced during measurement could be acounted for by simply assuming another hidden factor (X) such that A1 = func(α1, λ, X1) and A2 = func(α2, λ, X2) in which case A1 = func(α1, λ), A2 = func(α2, λ) may appear random and non-deterministic.

What's an example of a situation where it is violated?
I have given you two examples, one with coin tosses, another with doctors and patients. It is up to you to show the conspiracy in the two examples I gave that resulted in the violation.
I mean, in a real scientific experiment where the experimenters deliberately attempt to avoid any correlation between some "random" setting and some other factor.
This demonstrates a misunderstanding. In, the analogy I mentioned about flipping a coin and picking an individual randomly from physicsforums members. What if the experimenter knew nothing about the "hidden" parameter that the pool of people from which he was picking were members of a physics forum, how would he be able to make sure he has sampled randomly? Your error is to think that randomization enables you to screen-off any variable which you know nothing about.

I still can't understand you at all. Where in the world did you get the idea that Bell assumes that the "complete microscopic state" is the same, just because the angle is set the same?
Bell in his original 1964 paper said:
Since the initial quantum mechanical wavefunction does not determine the result of an individual measurement, this predetermination implies the possibility of a more complete specification of the state.
Let this more complete specification be effected by means of parameters λ. ...

It is obvious therefore from what you have accepted already in this thread that if the distribution of λ is the same in each run of the experiment, this means precisely that the *complete specification* of all the hidden parameters which resulted in the outcomes for that run, i.e, the list of all the actually realized λi values must be identical from one type of run to another. It doesn't matter in what order they appear in that list, all that matters is that they MUST in principle be sortable so that they now have the exact same order. This is what it means for the distribution to be identical. You agreed to this already!?

If you are now disagreeing with this then you are in effect saying you do not have any justification to factorize within the integral as you did. You cannot factorize a function and at the same time claim that the domain of the function was different from one term to the next. This can not be any clearer.

There is no assumption, and no need for any assumption, about the actual realized λs always being the same for a certain type of run, that the λs should come in exactly the same order for the different runs, or anything remotely like that.
First of all, I never said the order must be the same. I said the lists must in principle be sortable so that they have the exact same order. What do you think the domain of integration means for all the terms within the integral? That is why I used the discrete example so that you can understand the operation in terms of a list. If the domain of integration corresponds to 100 discrete λ values, then each function within the integral has the exact same domain of those 100 discrete values: λ1, λ2, ... λ100. If within the integral you have [E(a,λ)*E(b,λ) + E(a,λ)*E(cλ)]*p(λ), it is very clear that in the integral we performing an operation similar to:

[E(a,λ1)*E(b,λ1) + E(a,λ1)*E(cλ1)]*p(λ1)
+ [E(a,λ2)*E(b,λ2) + E(a,λ2)*E(cλ2)]*p(λ2)
+ [E(a,λ3)*E(b,λ3) + E(a,λ3)*E(cλ3)]*p(λ3)
...
+[E(a,λ100)*E(b,λ100) + E(a,λ100)*E(cλ100)]*p(λ100)

Now if you factor the terms the way you did within your integral to get something like:
[E(b,λ) + E(cλ)]*E(a,λ)*p(λ)

It is implicit that the exact domain of integration λ1, λ2, ... λ100, applies to each term and the same distribution p(λ1), p(λ2), p(λ3), ..., p(λ100) applies to each term. If that is not the case, then you have absolutely no justification for doing the factorization in the first place! Note the result of the factorization is that we end up with only 3 lists of numbers from which we could build the original paired products:

E(a,λi), i=1, 2, ... 100
E(b,λi), i=1, 2, ... 100
E(c,λi), i=1, 2, ... 100

Note also that, we could replace the probability weighted sum with a simple average by assuming that the domain of integration was not λ1, λ2, ... λ100, but rather a large number of trials in which the λs were realized at relative frequencies corresponding to their probability. In any case, once we have defined the domain of integration, it applies to every term within it. And we will still end up with ONLY 3 lists of outcomes in this reduced example.

These are the conditions which allow you to derive the inequality. These conditions must be true for the experiment to be used as a source of terms for the LHS of the CHSH. For the data from the experiment to be usable, the 8 lists of outcomes (4-paris) MUST be reduceable to 4 lists. Do you agree or disagree, you still have not answered this question.
Can I make it any simpler than that?
 
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  • #115
billschnieder said:
Aren't you saying in effect that A1 = func(α1, λ), and A2 = func(α2, λ)? Just because you mention it in words does not mean you do not have functions. The randomness you talk about, which is introduced during measurement could be acounted for by simply assuming another hidden factor (X) such that A1 = func(α1, λ, X1) and A2 = func(α2, λ, X2) in which case A1 = func(α1, λ), A2 = func(α2, λ) may appear random and non-deterministic.

I think this is an unimportant side issue, but writing A(a,λ) implies that there is some definite value of A that will be produced when the setting is a and the ... whatever ... is λ. That assumes determinism and is unnecessary in the derivation, so instead one should just say that the probabilities for the (two) possible values of A are determined jointly by (a,λ).



This demonstrates a misunderstanding. In, the analogy I mentioned about flipping a coin and picking an individual randomly from physicsforums members. What if the experimenter knew nothing about the "hidden" parameter that the pool of people from which he was picking were members of a physics forum, how would he be able to make sure he has sampled randomly?

Sample a bunch more and see if the statistics change.


Your error is to think that randomization enables you to screen-off any variable which you know nothing about.

You're not getting the point. The burden of proof lies on the other side, so to speak. We're talking about the kind of situation where, by ordinary scientific reason, you'd need some special reason -- some evidence -- to even suspect the kind of thing that you, instead, think should be assumed to exist until/unless there is some proof that it isn't happening. So it's not that I think that "randomization enables you to screen-off any variable you know nothing about" -- it's rather that the very idea that something is suitably "random" means that it isn't correlated up, in some fine-tuned way, with other things. This is never the kind of thing that can be proved in the way you seem to demand; rather it is a normal (and, usually, completely uncontroversial) background assumption lying behind the very project of empirical science.




It is obvious therefore from what you have accepted already in this thread that if the distribution of λ is the same in each run of the experiment, this means precisely that the *complete specification* of all the hidden parameters which resulted in the outcomes for that run, i.e, the list of all the actually realized λi values must be identical from one type of run to another. It doesn't matter in what order they appear in that list, all that matters is that they MUST in principle be sortable so that they now have the exact same order. This is what it means for the distribution to be identical. You agreed to this already!?

All it means for the distributions to be identical is that the lists have the same relative frequencies for the different values of λ (suitably coarse-grained if that's appropriate in the context of a given theory). Note that there is no reason we have to even measure the same exact number of particle pairs for the different joint settings! So surely it's way to strong to be insisting that "the lists have to be exactly the same" in the sense you describe here.


If the domain of integration corresponds to 100 discrete λ values, then each function within the integral has the exact same domain of those 100 discrete values: λ1, λ2, ... λ100. If within the integral you have [E(a,λ)*E(b,λ) + E(a,λ)*E(cλ)]*p(λ), it is very clear that in the integral we performing an operation similar to:

[E(a,λ1)*E(b,λ1) + E(a,λ1)*E(cλ1)]*p(λ1)
+ [E(a,λ2)*E(b,λ2) + E(a,λ2)*E(cλ2)]*p(λ2)
+ [E(a,λ3)*E(b,λ3) + E(a,λ3)*E(cλ3)]*p(λ3)
...
+[E(a,λ100)*E(b,λ100) + E(a,λ100)*E(cλ100)]*p(λ100)

Yes.


Now if you factor the terms the way you did within your integral to get something like:
[E(b,λ) + E(cλ)]*E(a,λ)*p(λ)

It is implicit that the exact domain of integration λ1, λ2, ... λ100, applies to each term and the same distribution p(λ1), p(λ2), p(λ3), ..., p(λ100) applies to each term.

I don't understand your point. The factored thing you just wrote here means (following your notation from above)

[E(b,λ1)+E(c,λ1)]*E(a,λ1)*P(λ1)
+ ...

But it sounds like you think this sum is somehow different than what you wrote above. Of course it is not. ?



If that is not the case, then you have absolutely no justification for doing the factorization in the first place! Note the result of the factorization is that we end up with only 3 lists of numbers from which we could build the original paired products:

E(a,λi), i=1, 2, ... 100
E(b,λi), i=1, 2, ... 100
E(c,λi), i=1, 2, ... 100

Why do you say this is a "result of the factorization"? It was already true that only these three functions were present. We just did ... trivial algebra. ?



Note also that, we could replace the probability weighted sum with a simple average by assuming that the domain of integration was not λ1, λ2, ... λ100, but rather a large number of trials in which the λs were realized at relative frequencies corresponding to their probability. In any case, once we have defined the domain of integration, it applies to every term within it. And we will still end up with ONLY 3 lists of outcomes in this reduced example.

I don't understand your point.


These are the conditions which allow you to derive the inequality. These conditions must be true for the experiment to be used as a source of terms for the LHS of the CHSH. For the data from the experiment to be usable, the 8 lists of outcomes (4-paris) MUST be reduceable to 4 lists. Do you agree or disagree, you still have not answered this question.
Can I make it any simpler than that?

You'll have to, as I don't understand. It sounds as if you're objecting to something that is, literally, a trivial piece of elementary algebra: factoring a common factor out of a binomial expression. I can't tell if that's your actual worry, or if instead you think that that's OK as math, but that somehow the experiments don't "live up to" the math.
 
  • #116
ttn said:
I don't know what that is supposed to mean. If anybody has an alternative superior definition of "locality" to propose, I'm all ears.

Einstein's definition of "local" works just fine for me.

ttn said:
Yes, the argument establishes that the perfect correlations (along an infinity of possible directions) require an infinity of pre-existing values -- if one assumes locality.

The argument is weak, imho. (Recall that I am offering my views on your article.) I believe it shows the authors' bias. I personally accept Einstein-locality with no need to accept what your "argument" purports to be the consequences.

ttn said:
I don't understand. It's not quite right to say the particles are unpolarized. They're in an entangled superposition wrt polarization. Are you saying the statistics can be explained by a local hidden variable theory? That's certainly wrong.

So why did Bell emphasise that the particles are unpolarised?

It seemed to me that he was making an important point?

As to the statistics, see below.

ttn said:
Incidentally, my middle name is "ty" so your pun is quite familiar!

My apologies. I tried to edit it out but was too late.

ttn said:
I looked at it briefly. I don't want to get sucked into a whole 'nuther thread. But it seems like your "challenge" involves asking people to calculate what the correlations will be like if the two photons are each in some polarization eigenstates (no entanglement). Of course the correlations will not violate any Bell/CHHS inequality in that case. If you think they do or might, you haven't understood the theorem at all. Also, in general, and returning the favor of your comments about they style of our article, I don't particularly like the style of posing "challenges" with some mysterious "gotcha" obviously waiting in the wings. If you think you've worked out a counterexample to Bell's theorem (which of course is preposterous, but nevermind that for now) then just put it out there and people will look at it and comment. Don't try to make us do your work for you.

As for style, my OP re "The Challenge" was presented as a question.

We now come to the matter of statistics and your failure to respond to a simple challenge.

I am not asking you to be "sucked-in" to another thread. I brought the challenge here, in what I thought was the spirit of the OP.

I would like to see the challenge addressed in the context of your article.

I was redrafting the introduction to the article for discussion here (seeking to be helpful). I was planning to show how I (a non-Bohmian) sees the challenge of BT.

So, I thought: What better place to start than with a realistic and Einstein-local (i.e., a wholly classical; and easily conducted) experiment?

But it seems that your imagined "Gotcha" has indeed GOTCHA! To be clear, I'm not asking you to do anything except give me your best thoughts on the challenge in the context of your article.

Your group holds themselves out to have some expertise re Bell's Theorem.

I would like to see that expertise applied to a realistic and Einstein-local (i.e., a wholly classical; and easily conducted) experiment?

So, please, do the maths or say why you cannot.

Is that too much to ask? Or too big a task?
..
 
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  • #117
ttn said:
Sample a bunch more and see if the statistics change.
But that is the point you continue to fail to understand. The fact that the statistics does not change does not mean the statistic you have is the appropriate one you are trying to calculate for the problem you have at hand! It's like trying to measure the average height of 100 people and you decide to measure 1 person's height 100 times. Just because your average converges does not mean you are calculating the correct average.

You're not getting the point. The burden of proof lies on the other side, so to speak.
On the contrary, it is you who do not get the point. You are the one doing the factorization to obtain the inequality, and then using experimental data, which do not obey the factorization requirements implicit in the derivation. It is up to you to demonstrate that the data you are comparing with the inequality is factorable. I have given you two examples in which the data was not factorable and the inequalities were violated without any conspiracy. One counter-example is enough to show how unreasonable your "no-conspiracy" assumption is. I gave you two.

I have explained from your proof and you have agreed that the terms in the CHSH are not independent of each other due to the cyclicity that permits you to do the factorization. Yet you take completely independent terms from QM and plug them into the LHS of the CHSH violating the very requirement which enables you to derive the inequalities. But for some reason, you translate this mathematical error on your part to the conclusion that locality is false.
So it's not that I think that "randomization enables you to screen-off any variable you know nothing about" -- it's rather that the very idea that something is suitably "random" means that it isn't correlated up, in some fine-tuned way, with other things.
First of all, it is not clear what you mean by suitable random. Secondly, in case you did not know, "random" simply means unpredictable. It doesn't mean there is no correlation. It simply means based on what you know, you can not discern a correlation. A system may appear random to one person and correlated to another who has more information about what is happening. But this is beside the point since the two examples I gave about doctors and coins decimates this line of argument of yours.

All it means for the distributions to be identical is that the lists have the same relative frequencies for the different values of λ (suitably coarse-grained if that's appropriate in the context of a given theory).
Even if we grant you the suggestion that the lists don't have to be the same length but only possesses the same relative frequency of each distinct λ value? You still can not escape because you already admitted that there is no way for the experimenters (having no information about λ) to make sure the same relative frequencies of λ are realized in the three different runs of the experiment. So there is no way to fulfil this requirement experimentally. As demonstrated by the examples I have illustrated,an infinite number of blind trials without any information of the parameters does not automatically give you the same λ distribution. In fact this can easily be seen by assuming that some combinations of λ and instrument settings lead to non-detection of the particle such that the coincidence circuitary discriminates against some λs by eliminating them from being considered for some angles. This will in fact cause you not to have the same λ distribution for each run. Do you think this is unreasonable? What is the conspiracy here?

Note that there is no reason we have to even measure the same exact number of particle pairs for the different joint settings! So surely it's way to strong to be insisting that "the lists have to be exactly the same" in the sense you describe here.

I'm not insisting. It is you who unknowinglys is insting that they must be, simply by carrying out the "trivial" algebra which you did in order to derive the inequality. I'm simply pointing out to you the implications of your "trivial" algebra. At least now you recognize that experiments can not fulfill this requirement which you relied on to derive the inequality.

Why do you say this is a "result of the factorization"? It was already true that only these three functions were present. We just did ... trivial algebra. ?
Exactly, you have only three (or 4 terms in the CHSH case) terms in deriving the inequality, but you do not have only 4 terms from an experiment, you have 8 terms in the form of lists of values. And those 8 terms cannot be reduced to 4 as required by your derivation. Get it?

Just in case you still do not understand, you derive the inequality starting with ONLY 4 terms E(a), E(b), E(c), E(a'). In the experiment you perform 4 separate runs (1,2,3,4). In the first you measure E1(a) and E1(b), in the second you measure E2(a) and E2(c), in the third you measure E3(a') and E3(b) and in the fourch you measure E4(a') and E4(c). In order for the terms from the experiment to comply with the requirements used in deriving the inequality,

E1(a) = E2(a)
E1(b) = E3(b)
E2(c) = E4(c)
E3(a') = E4(a')

This is the only way we end up with 4 terms like you used in your inequality. Note E(a) is a function not a number and saying two functions are equal means their codomain is identical for the same domain. And since you have already accepted that the domain of the function is the distribution of λ which is identical for each term, the outcomes of these functions must also be identical.

However, looking more carefully, you realize that the use of coincidence circuitary imples that in fact what is being measured is not E1(a), E2(a), E1(b), E3(b), E2(c), E4(c), E3(a'), E4(a') but instead
E1(a|b), E1(b|a) ie, the outcome at A1 with setting a, given that an outcome was also registered at A2 for setting b, etc
E2(c|a),E2(a|c),
E3(a'|b),E3(b|a'),
E4(a'|c), E4(c|a')

Which complicates things even further because now the requirement is that the following equalities must hold for the data to be usable on the LHS of the CHSH
E1(a|b) = E2(a|c)
E1(b|a) = E3(b|a')
E2(c|a) = E4(c|a')
E3(a'|b) = E4(a'|c)

So then, keeping in mind that the distribution of actually realized λ must be identical for all 4 terms. All you need for the experiment to violate the inequality is for any of the above equalities to be false, OR for certain λ values to be excluded from consideration by the coincidence circuitary for certain pairs of angles.

From what we know classically from Malus law, it is reasonable to expect the rate of coincidence detection to change with the angular difference and no amount of infinite trials can remedy this difficulty.

You'll have to, as I don't understand. It sounds as if you're objecting to something that is, literally, a trivial piece of elementary algebra: factoring a common factor out of a binomial expression. I can't tell if that's your actual worry, or if instead you think that that's OK as math, but that somehow the experiments don't "live up to" the math.
THe experiments don't live up to the math. It is so simple you could not see it. The error is hiding in plain sight. It might be trivial algebra, but many have been fooled by it. That is why you can't just gloss over it. Just in case you misunderstand again, I'm not questioning the algebra, I'm showing you the implications of it.
 
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  • #118
Here is an article which analyzes data from the Weihs et. al. experiment and show that there is a variation in coincidence count rate with angle (fig1) although single count rates do not vary with angle (fig3).

Which simply demonstrates that E(a|b) is different fro E(a).

http://arxiv.org/pdf/quant-ph/0606122

Look for example at figure 1. They say:
As can be seen in the coincidence rate figures (see figure 1a),
the coincidence rates exhibit minima close to zero, and cosine-squared shape, as
expected from the predictions of Quantum Mechanics. However, the maxima of the
four coincidence curves differ significantly. In spite of this anomalous behavior, the
correlation function computed with the standard normalization (i.e., with the sum of all
coincidence counts) coincides very well with the quantum mechanical predictions (see
figure 1b).
It is interesting to note that possibly similar anomalies were observed first in the
two-channel EPR experiments performed by Alain Aspect in Orsay in the early 1980’s.
The anomalies were reported in Aspect’s PhD Thesis [15] in the following words
For some measurements, we have observed abnormal differences between
coincidence rates that were expected to be equal (for instance N+− and N −+ ). It
turns out however that even for these measurements the correlation coefficient
E(a, b) remains equal to the quantum predictions, with better than two standard
deviations. We have no completely convincing explanation, either for these
anomalies, or for their compensation

...

The no-signalling principle being a fundamental feature of Quantum Mechanics, as
well as of Local Realism, the most reasonable interpretation of these anomalies is that
the Fair Sampling assumption should be rejected, as it is the only extra assumption
that we used to observe them.
 
  • #119
Gordon, Sorry but I'm not interested in engaging with these kinds of games. The sort of model you are toying with -- an obviously local model -- is going to make predictions that respect Bell's inequalities. You apparently think there is some big surprise waiting here, but there isn't. And if I'm wrong, I'm sure I'll hear about it when you present your results.

Bill, I think we have to agree to disagree about the reasonableness of the "no conspiracy" assumption. Your most recent (long) message does help me (to some extent) to understand what you are and aren't bothered by -- namely that it's the experiment "not living up to" the math as opposed to the math itself. But I still think you are profoundly wrong in how you are thinking about what the experiments are and/or should be. You are thinking of them as attempts to somehow recapitulate the steps in the derivation of the inequality. The truth is that the experiments simply measure the correlations, while the theorem is a proof that (under certain assumptions) the correlations are constrained in a certain way. There is simply no reason these two things should "look like each other" in anything like the way you seem to be demanding.

Thanks both for the stimulating discussion!
 
  • #120
ttn said:
Gordon, Sorry but I'm not interested in engaging with these kinds of games. The sort of model you are toying with -- an obviously local model -- is going to make predictions that respect Bell's inequalities. You apparently think there is some big surprise waiting here, but there isn't. And if I'm wrong, I'm sure I'll hear about it when you present your results.

Games? Is that what I was involved in when seriously annotating your article for comment?

Surprise? I'm surprised at your response (but should not have been).

But surely the big surprise is that YOU have so far been unable apply Bell's local-realistic protocol to a local-realistic experiment!

PS: The model that I'm employing is Bell's (1964) mathematical model of local-realism. I'm interested in how it fares in the analysis of a clearly local-realistic experiment.
 
  • #121
ttn said:
Bill, I think we have to agree to disagree about the reasonableness of the "no conspiracy" assumption. Your most recent (long) message does help me (to some extent) to understand what you are and aren't bothered by -- namely that it's the experiment "not living up to" the math as opposed to the math itself. But I still think you are profoundly wrong in how you are thinking about what the experiments are and/or should be. You are thinking of them as attempts to somehow recapitulate the steps in the derivation of the inequality.
No! I'm simply pointing out to you that you can not derive an inequality from ONLY 4 unique terms and reasonably expect an experiment which gives you 8 unique terms to satisfy the inequality! I'm simply pointing out that 2 inches + 2cm ≠ 4 inches, violates 2inches + 2inches = 4inches due to a simple violation of the mathematical definition of terms implicit in the equation, not due non-locality or any other spooky business. It is unreasonable to conclude that locality is ruled out without first demonstrating that the terms from QM or Experiment, correspond to the same terms you have in the inequallity. I believe I have have explained convincingly that they aren't.

Of course you are free to continue believing that they are just because of "ordinary scientific reason", whatever that means. But you have not provided any justification, let alone proof that they are.

The truth is that the experiments simply measure the correlations, while the theorem is a proof that (under certain assumptions) the correlations are constrained in a certain way. There is simply no reason these two things should "look like each other" in anything like the way you seem to be demanding.
There is no reason why "2inches" should look like "2cm" either, nor is there any reason why apples should look like oranges.

Thanks both for the stimulating discussion!
Thank you too. I hoped you will not bow out so soon.
 
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  • #122
billschnieder said:
No! I'm simply pointing out to you that you can not derive an inequality from ONLY 4 unique terms and reasonably expect an experiment which gives you 8 unique terms to satisfy the inequality!

Yes, I now understand that that's your worry. But I think it's just completely wrong headed and baseless. You somehow think that the experiments must sort of perfectly recapitulate all the steps in the derivation, but there is simply no reason at all it should work like that. Instead, the experiment should reflect the *assumptions* that go into the derivation -- in particular, the settings on each side should be made "at the last possible second" so that the kind of locality assumed in the derivation will apply if locality is true, and the ways those settings are made should be sufficiently independent of stuff going on at the source that one can accept that the "no conspiracies" assumption is reasonable.



It is unreasonable to conclude that locality is ruled out without first demonstrating that the terms from QM or Experiment, correspond to the same terms you have in the inequallity. I believe I have have explained convincingly that they aren't.

Well *of course* there's a sense in which "they aren't" -- the QM predictions, and also the experimental results, *don't respect the inequality*. That is the whole point! But I know it's not what you meant exactly. But I think you are coming at this all backwards. The goal is not to make the derivation somehow "reflect" what is happening in the experiments and/or in QM. The goal rather is to make the derivation respect the assumptions of "locality" and "no conspiracies" (and with no other assumptions). Then, when we do the experiments and find that the inequality is violated, we have to conclude that one of those assumptions is in fact false, i.e., does not apply to the actual experiment!

I hoped you will not bow out so soon.

More "winding down" than "bowing out". But it was becoming apparent that further intense discussion would not be likely to be fruitful.
 
  • #123
ttn said:
Yes, I now understand that that's your worry. But I think it's just completely wrong headed and baseless. You somehow think that the experiments must sort of perfectly recapitulate all the steps in the derivation, but there is simply no reason at all it should work like that. Instead, the experiment should reflect the *assumptions* that go into the derivation -- in particular, the settings on each side should be made "at the last possible second" so that the kind of locality assumed in the derivation will apply if locality is true, and the ways those settings are made should be sufficiently independent of stuff going on at the source that one can accept that the "no conspiracies" assumption is reasonable.

I think I have explained myself clearly enough and I think you have understood, although it appears you are still pre-disposed to rejecting the argument without having a genuine rebuttal to it. So I will wind this down as well with the following questions:

1. Are the terms in the CHSH independent terms or are they cyclically dependent on each other?
2. Are the terms calculated from QM and used to compare with the CHSH independent terms or cyclically dependent on each other.
3. Are the terms calculated from experimental results independent terms or are they cyclically dependent.

If you are reasoning correctly, and being honest with yourself, your answers will be

(1) Cyclically dependent
(2) Independent
(3) Independent

Now you claim that the reason the CHSH is violated is because QM is non-local and the experiments are non-local and the CHSH is local. But your answers to those questions will show that you have an additional assumption in the CHSH ie "cyclic dependency between terms" which is violated by both QM and the experiments. You have provided no argument why this is not a more reasonable explanation of the violation than non-locality.

Well *of course* there's a sense in which "they aren't" -- the QM predictions, and also the experimental results, *don't respect the inequality*.

QM and the experiments *don't respect the assumption of cyclic dependency between term* which is required to derive the inequality. You don't need to take my word for it. I have given two simple examples in which violation of cyclic dependency led to violation of the inequalities even though the situations were demonstrably locally causal. This should be enough for anyone who is interested in the truth. At the very least, it should give you pause the next time you proclaim the demise of locality.

But I think you are coming at this all backwards. The goal is not to make the derivation somehow "reflect" what is happening in the experiments and/or in QM.
But I just explained to you why the derivation does not "reflect" what is happening in the experiments and/or in QM! You may not like it, you may call it baseless and wrong but you have not provided any rebuttal that has stood up. You are the one who is clearly wrong.

The goal rather is to make the derivation respect the assumptions of "locality" and "no conspiracies" (and with no other assumptions). Then, when we do the experiments and find that the inequality is violated, we have to conclude that one of those assumptions is in fact false, i.e., does not apply to the actual experiment!
This is a cop-out. If that is what your goal was, you wouldl have started out with 8 unique functions and derived your inequality using those. Using 4 unique functions when you know fully well that experiments can only measure 8 unique functions is cheating not science. Unfortunately, many are continuously being misled by this.

In fact, cyclic dependency is the ONLY assumption required to derive the inequality as Boole showed, not locality or anything else. I encourage you to look up Booles conditions of possible experience, or Vorob'evs cyclicities.

Here is how to derive the inequalities without any physical assumption. This is how Boole did it:

Define a boolean variable v such that v = 0,1 and [itex]\overline{v} = 1 - v[/itex]
Now consider three such boolean variables x, y, z

It therefore follows that:

[itex]1 = \overline{xyz} + x\overline{yz} + x\overline{y}z + \overline{x}y\overline{z} + xy\overline{z} + \overline{xy}z + \overline{x}yz + xyz[/itex]
We can then group the terms as follows so that each group in parentheses can be reduced to products of only two variables.
[itex]1 = \overline{xyz} + (x\overline{yz} + x\overline{y}z) + (\overline{x}y\overline{z} + xy\overline{z}) + (\overline{xy}z + \overline{x}yz) + xyz[/itex]
Performing the reduction, we obtain:
[itex]1 = \overline{xyz} + (x\overline{y}) + (y\overline{z}) + (\overline{x}z) + xyz[/itex]
Which can be rearranged as:
[itex]x\overline{y} + y\overline{z} + \overline{x}z = 1 - (\overline{xyz} + xyz)[/itex]
But since the last two terms on the RHS are either 0 or 1, you can write the following inequality:
[itex]x\overline{y} + y\overline{z} + \overline{x}z \leq 1[/itex]
This is Boole's inequality. In Bell-type situations, we are interested not in boolean variables of possible values (0,1) but in variables with values (+1, -1) so we can define three such variables a, b, c where a = 2x - 1 , b = 2y - 1 and c = 2z -1, and remembering that
[itex]\overline{x} = 1 - x[/itex]
and substituting in the above inequality maintaining on the LHS only terms involving products of pairs, you obtain the following inequality
[itex]-ab - ac - bc \leq 1[/itex]
from which you can obtain the following inequality by replacing a with -a.
[itex]ab + ac - bc \leq 1[/itex]
[itex][/itex]
and then you can combine the above two inequalities into
[itex]|ab + ac| \leq 1 + bc[/itex]
which is a Bell-type inequality.

Note that the only assumption required here has been to suppose that we have three two-valued variables x,y,z. No locality, or other physical assumption is required to obtain the inequalities. It is obvious now why Bell or CHSH arrived at the same inequalities like Bell. They happened to be dealing with 3 bi-valued variables (4 in the case of CHSH) and by pushing some completely unneccessary math they fool themselves into thinking locality or no-conspiracy, or realism or any other physical assumption is required.

So then what do we make of violations of this inequality when obviously there is no other assumptions required to derive it, than "trival algebra of 3 two valued variables"? Violation simply means violation of trivial algebra of 3 two valued variables. As I have explained convincingly, the experiments violate it because:

1 - They are not dealing with 3 (or 4 for CHSH) two valued variables, they are dealing with 6 (or 8 for CHSH).
2 - Because of (1), they do not have 3 ( or 4 for CHSH) cyclically dependent terms. They have 4 independent terms.

And then they say, "Oh but experiments confirm QM". Of course, QM predictions are for independent terms and experiments produce independent terms so there is no surprise that they agree with each other and disagree with the inequality which requires cyclically dependent terms.

More "winding down" than "bowing out". But it was becoming apparent that further intense discussion would not be likely to be fruitful.
I suspect if you had a genuine rebuttal, you would present it.
 
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  • #124
billschnieder said:
1. Are the terms in the CHSH independent terms or are they cyclically dependent on each other?

I don't understand what you mean by "cyclically dependent".

(I don't understand exactly what you think you mean by "independent" either for that matter. Of course there are senses in which the 4 terms, as calculated say in QM, are independent, and senses in which they aren't.)


you have an additional assumption in the CHSH ie "cyclic dependency between terms"

As I said, I don't understand what you even mean by this "cyclic dependency", but -- assuming you mean to be referring to some property that is actually there -- it is *not* an *additional assumption* but rather something that *follows* from the assumptions that are *actually made*. Otherwise you'd be able to tell me where the mistake in the mathematical derivation is.



QM and the experiments *don't respect the assumption of cyclic dependency between term* which is required to derive the inequality.

There's no such assumption. We are extremely clear and explicit about things that are being assumed. You're objecting to something (I don't fully understand what) "downstream". But all the math that gets you down that stream is trivial. Tell me what's wrong with the actual premises, or with the reasoning.


In fact, cyclic dependency is the ONLY assumption required to derive the inequality as Boole showed, not locality or anything else.

It is undoubtedly true that other assumptions (than the ones we use) can lead to the same conclusion, Bell's inequality. For example, any physics textbook will show how to derive the inequality from the assumption of "local deterministic non-contextual hidden variables". (See our section 8 for some discussion.) Perhaps it's also true that the inequality can be derived from "cyclic dependency". Who cares? None of those alternative starting points have anything like the status of "locality" -- that, I take it, is your point. But if

A --> C

and

B --> C

and you find out C is false, it's not like you get to *choose* which derivation of C you like best, and hence which of A or B you would prefer to reject.
 
  • #125
ttn said:
I don't understand what you mean by "cyclically dependent".

Seriously!?

|ab + ac| - bc <= 1, Bell's 3-term inequality for example
Cyclic Dependency means every product shares one term with another product (ie ab, ac, bc)
for ONLY three distinc terms a,b,c.
NEVER violated unless due to mathematical or logical error!
Proof:
a,b,c = (+1,+1,+1): |(+1) + (+1)| - (+1) <= 1, obeyed=True
a,b,c = (+1,+1,-1): |(+1) + (-1)| - (-1) <= 1, obeyed=True
a,b,c = (+1,-1,+1): |(-1) + (+1)| - (-1) <= 1, obeyed=True
a,b,c = (+1,-1,-1): |(-1) + (-1)| - (+1) <= 1, obeyed=True
a,b,c = (-1,+1,+1): |(-1) + (-1)| - (+1) <= 1, obeyed=True
a,b,c = (-1,+1,-1): |(-1) + (+1)| - (-1) <= 1, obeyed=True
a,b,c = (-1,-1,+1): |(+1) + (-1)| - (-1) <= 1, obeyed=True
a,b,c = (-1,-1,-1): |(+1) + (+1)| - (+1) <= 1, obeyed=True

(Note that only 8 distinct possibilities exist for combinations of the values of a,b,c)
(Note also that the inequality is NEVER violated, NEVER!
It is a logical/mathematical error to expect the inequality to be satisfied by 6 distinct terms
|a1b1 + a2c2| - b3c3 <= 1, is WRONG! There is no cyclicity present, UNLESS a1=a2 and b1=b3 and c2=c3
Proof:
a1,a2,b1,b3,c2,c3 = (+1,+1,+1,+1,+1,+1): |(+1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,+1,+1,+1,+1,-1): |(+1) + (+1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (+1,+1,+1,-1,+1,+1): |(+1) + (+1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (+1,+1,+1,-1,+1,-1): |(+1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,+1,+1,+1,+1): |(+1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,+1,+1,+1,-1): |(+1) + (-1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,+1,-1,+1,+1): |(+1) + (-1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,+1,-1,+1,-1): |(+1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,+1,+1,+1,-1,+1): |(+1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,+1,+1,+1,-1,-1): |(+1) + (-1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,+1,+1,-1,-1,+1): |(+1) + (-1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,+1,+1,-1,-1,-1): |(+1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,+1,+1,-1,+1): |(+1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,+1,+1,-1,-1): |(+1) + (+1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (+1,-1,+1,-1,-1,+1): |(+1) + (+1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (+1,-1,+1,-1,-1,-1): |(+1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,+1,-1,+1,+1,+1): |(-1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,+1,-1,+1,+1,-1): |(-1) + (+1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,+1,-1,-1,+1,+1): |(-1) + (+1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,+1,-1,-1,+1,-1): |(-1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,-1,+1,+1,+1): |(-1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,-1,+1,+1,-1): |(-1) + (-1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (+1,-1,-1,-1,+1,+1): |(-1) + (-1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (+1,-1,-1,-1,+1,-1): |(-1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,+1,-1,+1,-1,+1): |(-1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,+1,-1,+1,-1,-1): |(-1) + (-1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (+1,+1,-1,-1,-1,+1): |(-1) + (-1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (+1,+1,-1,-1,-1,-1): |(-1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,-1,+1,-1,+1): |(-1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,-1,+1,-1,-1): |(-1) + (+1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,-1,-1,-1,+1): |(-1) + (+1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (+1,-1,-1,-1,-1,-1): |(-1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,+1,+1,+1,+1): |(-1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,+1,+1,+1,-1): |(-1) + (+1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,+1,-1,+1,+1): |(-1) + (+1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,+1,-1,+1,-1): |(-1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,+1,+1,+1,+1): |(-1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,+1,+1,+1,-1): |(-1) + (-1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (-1,-1,+1,-1,+1,+1): |(-1) + (-1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (-1,-1,+1,-1,+1,-1): |(-1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,+1,+1,-1,+1): |(-1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,+1,+1,-1,-1): |(-1) + (-1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (-1,+1,+1,-1,-1,+1): |(-1) + (-1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (-1,+1,+1,-1,-1,-1): |(-1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,+1,+1,-1,+1): |(-1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,+1,+1,-1,-1): |(-1) + (+1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,+1,-1,-1,+1): |(-1) + (+1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,+1,-1,-1,-1): |(-1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,-1,+1,+1,+1): |(+1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,-1,+1,+1,-1): |(+1) + (+1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (-1,+1,-1,-1,+1,+1): |(+1) + (+1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (-1,+1,-1,-1,+1,-1): |(+1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,-1,+1,+1,+1): |(+1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,-1,+1,+1,-1): |(+1) + (-1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,-1,-1,+1,+1): |(+1) + (-1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,-1,-1,+1,-1): |(+1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,-1,+1,-1,+1): |(+1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,-1,+1,-1,-1): |(+1) + (-1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,-1,-1,-1,+1): |(+1) + (-1)| - (-1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,+1,-1,-1,-1,-1): |(+1) + (-1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,-1,+1,-1,+1): |(+1) + (+1)| - (+1) <= 1, obeyed=True
a1,a2,b1,b3,c2,c3 = (-1,-1,-1,+1,-1,-1): |(+1) + (+1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (-1,-1,-1,-1,-1,+1): |(+1) + (+1)| - (-1) <= 1, obeyed=False
a1,a2,b1,b3,c2,c3 = (-1,-1,-1,-1,-1,-1): |(+1) + (+1)| - (+1) <= 1, obeyed=True

(Note that 64 distinct possibilities exist for combinations of the values of a,b,c)
(Note that when a1=a2 and b1=b3 and c2=c3, the inequality is NEVER violated)
(Note that the inequality is violated when the above equalities are not obeyed, ie we can not reduce the 6 terms to 3 unque terms)
 
  • #126
ttn said:
As I said, I don't understand what you even mean by this "cyclic dependency", but -- assuming you mean to be referring to some property that is actually there -- it is *not* an *additional assumption* but rather something that *follows* from the assumptions that are *actually made*. Otherwise you'd be able to tell me where the mistake in the mathematical derivation is.

Now explain to me what about locality or no-consipriacy or any other physical assumption youlike led you to say the following in the article:

Bell's inequality theorem. Consider random variables Ziα , i=1,2 , α=a,b,c , taking only the values ±1 . If these random variables are perfectly anti-correlated, i.e., if Z1α=−Z2α , for all α , then:

(1)P(Z1a≠Z2b)+P(Z1b≠Z2c)+P(Z1c≠Z2a)≥1.

...

Theorem. Suppose that the possible values for A1 and A2 are ±1 . Under the mathematical setup described above, assuming the factorizability condition (4), the following inequality holds:

|C(a,b)−C(a,c)|+|C(a′,b)+C(a′,c)|≤2,

- For the CHSH case, why a,b,c,a', and not a1,b1,a2,c2,a'3,b3,a'4,c4 so that the first run measures "a1,b1", the second measures "a2,c2" the third measures "a'3,b3" and the fourth measures "a'4,c4". Why don't you start with the 8 terms and prove the inequality using those?
- For the Bell Case |ab + ac| - bc <= 1, why start with "a,b,c" and not "a1,b1,a2,bc2,b3,c3?

This is crystal clear, you are just stubbornly standing your ground even though you understand what I'm asking very well and you have no answer for it.

There's no such assumption. We are extremely clear and explicit about things that are being assumed.
Then you will have no difficulty answering the above questions. What in the world made you to start with 4 terms instead of 8 for CHSH, and 3 terms instead of 6 for Bell.

You're objecting to something (I don't fully understand what) "downstream". But all the math that gets you down that stream is trivial.
I think you understand very well but don't like it. You are making a trivial mistake which I've pointed out from many different angles in this thread and yet you continue to dodge without providing any counter-argument, claiming not to understand it.
It is undoubtedly true that other assumptions (than the ones we use) can lead to the same conclusion, Bell's inequality.
...
Perhaps it's also true that the inequality can be derived from "cyclic dependency". Who cares? None of those alternative starting points have anything like the status of "locality" -- that, I take it, is your point.
Bah, "cyclic dependenty" is present in EVERY proof. EVERY proof can be reduced to:

(1) Blah, Blah, ... Blah Blah,
(2) Therefore XY + XZ + YZ >= 1 *** <- Cyclic dependency! Required by ALL PROOFS.
(3) ...

Step 1 "Blah blah blah" is just a smokescreen it doesn't matter at all what (1) is so long as you do (2) you will arrive at the inequalities. Violation of the inequalities is not violation of (1), it is violation of (2). This is crystal clear. Cyclic dependency is not an alternate assumption. It is THE most important assumption present in ALL proofs.

But if

A --> C

and

B --> C

and you find out C is false, it's not like you get to *choose* which derivation of C you like best, and hence which of A or B you would prefer to reject.

But that is exactly what you have done. You have picked "locality" to reject even though you know fully well that other assumptions give you the same conclusion. However, as I've clearly explained this is not my point.

My point is more like:

A --> X --> C
and
B --> X --> C
and
X --> C

If C is false, it is X that has been violated not A or B. X is a necessary and sufficient condition to obtain C. A and B are not. The fact that X is trivial algebra does not mean it is not being violated.
 
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  • #127
May be the best way to resolve this debate is for someone to analyze the actual experimental data and report their findings. Or, if possible, post the data in a convenient form on this forum (or link) for others to examine. Once sorted, Bell's inequality may be tested using the 3 or 6 data sequences suggested by Bill in this thread. Hopefully, the finished analysis will show if Bell’s inequality can tell us anything about the locality or non-locality of nature.
 
  • #128
billschnieder said:
... I suspect if you had a genuine rebuttal, you would present it.

Gee Bill, I think you are close to bringing the entire scientific establishment to its knees.

:biggrin:
 
  • #129
rlduncan said:
May be the best way to resolve this debate is for someone to analyze the actual experimental data and report their findings.

This thread is actually about the Scholarpedia article. It is actually not a debate about Bell itself. Not supposed to be, anyway.
 
  • #130
I agree. Except that tnn stated that "Anyway, hopefully people will at some point get around to actually reading the thing and then raising questions about the proofs, arguments, definitions, etc." The factoring step for the derivation of the CHSH inequality has been questioned as to the applicability to the EPR experiments. This may also be resolved using the Bell inequality.
 
  • #131
billschnieder said:
Now explain to me what about locality or no-consipriacy or any other physical assumption youlike led you to say the following in the article:

I don't know how to answer that except to say: try reading the article and trying to follow the arguments presented.


- For the CHSH case, why a,b,c,a', and not a1,b1,a2,c2,a'3,b3,a'4,c4 so that the first run measures "a1,b1", the second measures "a2,c2" the third measures "a'3,b3" and the fourth measures "a'4,c4". Why don't you start with the 8 terms and prove the inequality using those?
- For the Bell Case |ab + ac| - bc <= 1, why start with "a,b,c" and not "a1,b1,a2,bc2,b3,c3?

Um, "a" and "b" and "c" are three possible angles along which the polarizations might be made. These 3 possibilities simply aren't "indexed" to a particular run in the way you're describing.

This is crystal clear, you are just stubbornly standing your ground even though you understand what I'm asking very well and you have no answer for it.

Yes, I know you think it's clear, but what you're demanding actually makes no sense at all.



But that is exactly what you have done. You have picked "locality" to reject even though you know fully well that other assumptions give you the same conclusion. However, as I've clearly explained this is not my point.

My point is more like:

A --> X --> C
and
B --> X --> C
and
X --> C

If C is false, it is X that has been violated not A or B. X is a necessary and sufficient condition to obtain C. A and B are not. The fact that X is trivial algebra does not mean it is not being violated.

Now I'm starting to think you don't understand elementary logic. If A --> X --> C, and B --> X --> C, and X --> C, and C is false, then all three of A, B and X are false.

I think you'd be hard pressed to show that X --> C, though (i.e., that this phantom notion you call, dubiously, "cyclic dependency", implies Bell's inequality). I'll wait for the paper where you explain that.

The real point, though, is that you can assume locality ("A" above) and then *do math*, and you get the inequality. The thing you're calling "X" is actually just some step along the way in the math -- *not* anything like an *assumption*. What you're saying is basically equivalent to this: you can't derive a Bell inequality without using a plus sign, so maybe we should blame the violation of the inequalities on the use of plus signs, instead of saying that they prove nonlocality.
 
  • #132
ttn said:
I don't know how to answer that except to say: try reading the article and trying to follow the arguments presented.
You present no argument why ALL BELL/CHSH proofs all of a sudden decide to postulate cyclic dependency between terms. Now you have no excuse for not understanding what I mean by cyclic dependency. Here again I present the evidence from your article:

Bell: P(Z1a≠Z2b)+P(Z1b≠Z2c)+P(Z1c≠Z2a)≥1. Why three angles, why make the terms cyclically dependent? WHY? What about locality or no-conspiracy makes it necessary for you to introduce cyclic dependency into the terms? You have no answer.

CHSH: |C(a,b)−C(a,c)|+|C(a′,b)+C(a′,c)|≤2,. Why 4 angles, why make the terms cyclically dependent? WHY? What about locality or no-conspiracy makes it necessary for you to introduce cyclic dependency between the terms? You have no answer.

All you gave is:

(1) Blah, Blah, ... Blah Blah,
(2) Therefore XY + XZ + YZ >= 1 *** <- Cyclic dependency! Required by ALL PROOFS.
(3) ...

You can not even prove that any physical assumption is required. In fact, (1) can be any thing whatsoever, so long as it involves 3 variables X,Y, Z of value ±1. I have enumerated all the possibilities in a recent post. To which you had absolutely nothing to say in response.

Um, "a" and "b" and "c" are three possible angles along which the polarizations might be made. These 3 possibilities simply aren't "indexed" to a particular run in the way you're describing.
Why not? So you set the instrument angle to "a" and then you collect a series of outcomes ±1. Except you forget that what is actually measured is not the list of outcomes when the instrument was set at angle "a". For the Bell case here is what you are measuring (considering the angle "a", only):

Run 1:
- outcome when instrument is set at "a" given that a corresponding outcome was measured at the other station with that instrument set at "b". ie (a|b)

Run 2:
- outcome when instrument is set at "a" given that a corresponding outcome was measured at the other station with that instrument set at "c". ie (a|c)

Now you don't need to be a rocket scientist so realize how naive it is to assume that (a|b) = (a|c). So clearly there is every justification for indexing the angles appropriately. From what you know from classical physics, it is in fact stupid to assume that the two are equivalent.

I think you'd be hard pressed to show that X --> C, though (i.e., that this phantom notion you call, dubiously, "cyclic dependency", implies Bell's inequality). I'll wait for the paper where you explain that.

No need to wait. See post #125 above for the proof, or any of the published articles I cited earlier in the thread.

The thing you're calling "X" is actually just some step along the way in the math -- *not* anything like an *assumption*.
Call it whatever you like. The point is that you can not obtain the inequality without it, and it is violated by the data gathering and manipulation procedues of experiments.
What you're saying is basically equivalent to this: you can't derive a Bell inequality without using a plus sign, so maybe we should blame the violation of the inequalities on the use of plus signs, instead of saying that they prove nonlocality.
No. Despite your caricature attempt, your position is that since it is OK to use a plus sign, it must be okay to say 2 inches + 2 cm ≠ 4 inches violates the equality 2 + 2 = 4. My position is that you are not adding the same type of thing as implied by the equation. So what you are violating is the mathematical equivalence of the terms in the equation. What the experiments are violating is the cyclicity required to derive the inequality as demonstrated in post #125. You have no answer for that.
 
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  • #133
I encourage anyone interested in this discussion to read the following article

ITAMAR PITOWSKY
George Boole's 'Conditions of Possible Experience' and the Quantum Puzzle
Brit. J. Phil. Sci. 45 (1994). 95-125

Excerpts:
In the mid-nineteenth century George Boole formulated his 'conditions of possible
experience'. These are equations and inequalities that the relative frequencies of
(logically connected) events must satisfy. Some of Boole's conditions have been
rediscovered in more recent years by physicists, including Bell inequalities, Clauser
Home inequalities, and many others.
...
CAN BOOLE'S CONDITIONS BE VIOLATED?
One thing should be clear at the outset: none of Boole's conditions of possible
experience can ever be violated when all the relative frequencies involved have been
measured in a single sample. The reason is that such a violation entails a logical
contradiction.
...
In case we deal with relative frequencies in a single sample, a violation of any of the relevant Boole's
conditions is a logical impossibility.
...
But sometimes, for various reasons, we may choose or be forced to measure
the relative frequencies of (logically connected) events, in several distinct
samples.In this case a violation of Boole's conditions may occur. There are
various possible reasons for that, and they are listed below in an increasing
order of abstractness:
(a) Failure of randomnes...
(b) Measurement biases...
(c) No distribution...
(d) Mathematical oddities...
...
These are the cases, of which I am aware, where Boole's conditions might be
violated. Another possibility, which has been neglected, is the case where we
erroneously believe that some logical relation among the events obtains, and
thus, wrongly expect some condition to be satisfied. Strictly speaking, this case
does not represent a violation of Boole's conditions, but rather an error of
judgement.
 
  • #134
ttn said:
Could you say exactly what you thought was inaccurate? I couldn't understand, from what you wrote, what you had in mind exactly.
I could, but that doesn't belong in the QM group. In a nutshell, your definitions imply or suggest that people such as Lorentz and Bell did not teach special relativity when they claimed to teach a theory which they called special relativity and which Einstein and others clearly labeled as such. If you like, we could discuss it further with private messages, or start a post in the relativity group about it.
My point here was that, regretfully, this gave me the impression that your article is based on rather superficial (and thus potentially inaccurate) information that was directly taken from other books and papers, without digging sufficiently deeper - like one would expect of Wikipedia, but of course not what you intended for "Scholarpedia".
 
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  • #135
billschnieder said:
You present no argument why ALL BELL/CHSH proofs all of a sudden decide to postulate cyclic dependency between terms.

But, for the hundredth time, they *don't* POSTULATE any such thing. Whatever exactly it is that you are objecting to is a CONSEQUENCE of the assumptions, not an additional assumption.

Bell: P(Z1a≠Z2b)+P(Z1b≠Z2c)+P(Z1c≠Z2a)≥1. Why three angles, why make the terms cyclically dependent? WHY? What about locality or no-conspiracy makes it necessary for you to introduce cyclic dependency into the terms? You have no answer.

One is of course free to consider whatever experimental setups one chooses. This happens to be the combination of setups that Bell's theorem is *about*. That's why this particular set of setups is considered. But "Here are some assumptions which, if true, should apply to any setup; let's consider these 3 setups to get an interesting result" is hardly the same as introducing some controversial new postulate.


All you gave is:

(1) Blah, Blah, ... Blah Blah,
(2) Therefore XY + XZ + YZ >= 1 *** <- Cyclic dependency! Required by ALL PROOFS.
(3) ...

You can not even prove that any physical assumption is required. In fact, (1) can be any thing whatsoever, so long as it involves 3 variables X,Y, Z of value ±1. I have enumerated all the possibilities in a recent post. To which you had absolutely nothing to say in response.

The 1/2/3 above is, I'm sure, an accurate description (i.e., confession) of the state of your consciousness in trying to follow the argument. That is, you haven't grasped it as an argument at all, but you instead just zone out during the whole explication of premises. But, it's a logical argument whether you sleep through the first part or not. And if you object to something in the middle, you should have the integrity -- the curiosity -- to try to trace that thing you object to back to the premises, to find out exactly where it came from and how the premises do or don't support it, instead of just dismissing the whole thing as "blah blah blah".



Now you don't need to be a rocket scientist so realize how naive it is to assume that (a|b) = (a|c).

But THIS IS NOT AN ASSUMPTION. It is rather something that FOLLOWS from the assumptions that are actually, explicitly made -- locality here in particular. The "blah blah blah" part that you slept through includes an explicit acknowledgment of the assumption that the outcome on one side might be allowed to depend on the setting on that side and on the pre-measurement state of the particles, but should not depend on the distant setting. (Your notation is also vague in the sense that the "no conspiracy" assumption is also partly responsible for what you evidently mean here: if the "pre-measurement state of the particles" depended on the distant setting, that would be another way that in principle the distant setting could affect the nearby outcome. This possibility however is excluded by the assumption that the "pre-measurement state of the particles" does not depend on the settings, i.e., the "no conspiracy" assumption.)


So clearly there is every justification for indexing the angles appropriately. From what you know from classical physics, it is in fact stupid to assume that the two are equivalent.

Obviously I don't agree with the last sentence. But logically the main point is that any "justification for indexing the angles appropriately" will constitute a denial of one or both of "locality" and "no conspiracies".


We have both made our positions clear, and I have to say that arguing with you just frankly isn't all that enjoyable. So feel free to have the last word if you want it, but I won't continue arguing with you any further. It's clear that nothing will come of it. People still watching the discussion will then have to make up their own minds.
 
  • #136
harrylin said:
I could, but that doesn't belong in the QM group. In a nutshell, your definitions imply or suggest that people such as Lorentz and Bell did not teach special relativity when they claimed to teach a theory which they called special relativity and which Einstein and others clearly labeled as such. If you like, we could discuss it further with private messages, or start a post in the relativity group about it.
My point here was that, regretfully, this gave me the impression that your article is based on rather superficial (and thus potentially inaccurate) information that was directly taken from other books and papers, without digging sufficiently deeper - like one would expect of Wikipedia, but of course not what you intended for "Scholarpedia".

I don't think any huge discussion is needed here, and this thread seems like a perfectly good place to have a short one, since after all your comments are about the scholarpedia article.

You suggest that our understanding/presentation of what constitutes "relativity" is superficial/thin. I (perhaps not surprisingly) think that's just backwards, and actually it's the way most people talk that is inappropriately superficial. "Special relativity" does not refer merely to a certain set of equations that one finds in relativity textbooks; it refers to a certain *physical theory* which involves various, um, ontological commitments. In particular, what normal physicists mean by "special relativity" includes the *denial of the idea that there is a dynamically privileged reference frame aka ether*. This is partly a historical issue. Lorentz had proposed a theory in which there was a dynamically privileged reference frame or "ether" -- the same thing that everybody just assumed existed in the context of Maxwell's electromagnetic theory -- but in which a certain rather strange mathematical symmetry in effect conspired to make it impossible for us to empirically detect our motion through this ether. Let's call this view "Lorentzian relativity" -- it is of course the view that Bell was describing in his lovely "how to teach" article.

The point is: then Einstein came along and proposed what is now usually called "special relativity" -- though let's call it "Einsteinian relativity" here for the purpose of extra clarity. According to "Einsteinian relativity", there *is no ether*; instead, all reference frames are fundamentally, dynamically equivalent.

Now it sounds like you want to say that both "Einsteinian relativity" and "Lorentzian relativity" are perfectly well subsumed under "special relativity" -- they are merely different interpretations of "special relativity", or something like that. I actually think that is right, and I certainly think that "Lorentzian relativity" is a going option, i.e., that no experiment has refuted it as a possibility. But here I openly acknowledge being in a great minority among regular physicists. If you ask any normal physicist whether "special relativity" is compatible with the possible existence of an ether, a dynamically privileged reference frame, they will say "no bleeping way!" and never talk to you again! =)

So, for purposes of communication, we tend to use the phrase "special relativity" to mean basically what most other people use that phrase to mean. But of course, in the discussion, we explicitly distinguish the "Einsteinian" and "Lorentzian" views, distinguish the idea of "relativity at the level of what can be observed" (which is compatible with both Einsteinian and Lorentzian approaches) and "fundamental relativity" (which the Lorentzian approach violates), etc. This is all more or less exactly following Bell, who for example notes repeatedly that Bohmian Mechanics (in so far as it requires a dynamically privileged reference frame, or some equivalent) fails to respect fundamental relativity, etc. It's true that in his "how to teach" article he described himself as teaching "special relativity", but I think it's clear that here he was doing a kind of propaganda, i.e., trying to "soft sell" an idea that, if presented more bluntly, causes normal physicists to simply shut down and stop listening (because they have been dogmatized against the Lorentzian view to the point that they believe, erroneously, that it was somehow experimentally refuted by the MM exp or whatever).

Basically the main point is just that it's incredibly easy to reconcile non-locality (which remember we know is there because of Bell's theorem and the experiments) with "lorentzian relativity" -- Bell always called this "the simplest solution", etc., and we agree. Indeed, since we all like Bohmian Mechanics, we are quite happy to agree! But reconciling quantum non-locality with *Einsteinian relativity* -- i.e., what most normal physicists think of as just plain "relativity" -- is much harder. It can in principle be done, sort of, probably. (See for example Tumulka's relativistic GRW model.) But it's very very difficult, and it's basically an open question whether non-locality can be reconciled with "fundamental relativity" in the context of a "fully serious" theory (e.g., something that makes all the predictions of ordinary QFT).

Do you disagree with any of this? Or do you merely prefer using the words "special relativity" in a less narrow way, like the way Bell evidently uses them in "how to teach"?
 
  • #137
ttn, seriously I don't know how can you be so patient.

To the rest: there is a mathematical threorem "The CHSH-Bell Inequality: Bell's Theorem without perfect correlations". As far as I could check, the mathematical proof (of the precise mathematical statement) is correct.

I don't even care the names we put to the two premises ("mathematical setup" + "factorization condition", or "mathematical general structure capturing the possible ways a theory produces numerical predictions" + "locality", or "mathematical general structure capturing the possible ways a theory produces numerical predictions" + "separability", whatever...), or the name we put to the thesis of that mathematical theorem, because no words can be as precise as a mathematical statement itself.

So, is there anyone else here (apart from me) that actually has tried to check if the mathematical proof is correct or not?
 
  • #138
Maybe you think by shouting the contrary, you are actually refuting my argument, but you are not. And since you continue to misrepresent my argument, I will continue to clarify it.
ttn said:
But, for the hundredth time, they *don't* POSTULATE any such thing. Whatever exactly it is that you are objecting to is a CONSEQUENCE of the assumptions, not an additional assumption.
Look, I can grant to you that the factorizability condition is a consequence of an assumption. However it is a lie that the cyclicity implied in P(Z1a≠Z2b)+P(Z1b≠Z2c)+P(Z1c≠Z2a)≥1 is due to any physical assumption. You could simply have said Bell picked those ones because they worked. There is no reason in your paper or any other Bell-type proof why Bell picked P(Z1a≠Z2b)+P(Z1b≠Z2c)+P(Z1c≠Z2a), instead of say P(Z1a≠Z2b)+P(Z1c≠Z2d)+P(Z1e≠Z2f) and you know it. Nothing about Locality or no-conspiracy forces you to pick the former and not the latter. The only reason that can be infered from it is "because it works". In other words, the latter would have given an inequality which is NEVER violated by QM or Experiments.

Now I have carefully explained to you that the reason why it works is BECAUSE of the cyclicity, that is why NO Bell-type proofs use the non-cyclical type P(Z1a≠Z2b)+P(Z1c≠Z2d)+P(Z1e≠Z2f). I even posted a simulation using all possible values, clearly demonstrating the importance of the cyclicity. To which you had absolutely nothing so say. So contrary to what you like, the cyclicity is the most important component of the proof. Call it "trival agebra" or whatever you like, it still doesn't change this fact.

One is of course free to consider whatever experimental setups one chooses.
Exactly, and there is nothing about locality or no-conspiracy that forces ALL Bell proofs to use ONLY the ones that involve cyclicity but not the ones without cyclicity. I suspect you will respond that you do not understand what cyclicity means, or completely ignore it as you have been doing.

This happens to be the combination of setups that Bell's theorem is *about*. That's why this particular set of setups is considered.
But you do not deny that for three separate runs, the experiments are measuring a1,b1,a2,c2,b3,c3 (six separate terms). All you argue is that a1=a2, b1=b3, c2=c3, naively thinking that the the angles are the only parameters relevant for the outcomes and making the logical error of equating the outcomes. Your (and Bell's) only justification is the assumption that the distribution of hidden parameters is identical for each term. You then make the leap to argue that the only way this assumption can be violated is if there is nonlocality or no-conspiracy. But as I've explained, this is just plain naive.

Bell is assuming that in such an experiment "When the instrument is set to the angle 'a', the distribution of all hidden parameters which affect the outcome is exactly identical from one run of the experiment to the next". Note that failure of this assumption implies that the cyclicity is broken and the inequality can be violated as demonstrated by Boole 100 years before Bell, and as proven in my simulation in post #125.

I have already explained in this thread that the way experiments are performed using coincidence circuitary, the experimenters are not measuring simply "Outcomes when angle is set at 'a'" but they are measuring "Outcomes when angle is set at 'a' given that an outcome is also measured at the other station with it's angle set at 'b'". If you think the two are the same or that the latter violates no-conspiracy or locality, then you lack basic understanding of logic and probability theory.

I have demonstrated convincingly that experiments violate the cyclicity by measuring and using 6 different terms rather than the 3 used by Bell. I have also demonstrated that it is unreasonable to expect the cyclicity to be maintained given what we know about light from classical physics. Therefore violation of the inequality says absolutely nothing about locality or no-conspiray. Violation simply implies violation of the cyclicity. Boole recognized this 100 years before Bell and he did not question locality/reality the way those with a penchant for mysticism are prone to doing these days.

Obviously I don't agree with the last sentence. But logically the main point is that any "justification for indexing the angles appropriately" will constitute a denial of one or both of "locality" and "no conspiracies".
Now let us break down what this implies about what you believe:

- You believe contrary to Malus law that the angular difference between the two sides, does not affect the rate of coincidence detection.
- You believe that every property of the complete system "instrument + particle" relevant for the outcomes actually observed are identical when "a" is measured coincidentally with "b" and when "a" is measured with "c", despite the fact that the angle between "a" and "b" is different from the angle between "a" and "c".
- You believe only conspiracy or non-locality can explain why all relevant properties of the complete system of "instrument + particle" for two separate runs, performed at different times, and filtered using coincidence circuitary governed by a different angular differences might be different, so long as they used the same macroscopic angle setting.

What a naive view of physics. Funding agencies may be fooled by this kind of "snake-oil". Not me.
 
  • #139
mattt said:
ttn, seriously I don't know how can you be so patient.

To the rest: there is a mathematical threorem "The CHSH-Bell Inequality: Bell's Theorem without perfect correlations". As far as I could check, the mathematical proof (of the precise mathematical statement) is correct.
If you were following carefully you would have understood that I'm not questioning the math. Rather I'm questioning the suggestion and common errorneous practice of using terms from QM and experiments on the LHS of the inequalities.
 
  • #140
billschnieder said:
If you were following carefully you would have understood that I'm not questioning the math. Rather I'm questioning the suggestion and common errorneous practice of using terms from QM and experiments on the LHS of the inequalities.

But then you won't agree either with other versions (weaker than this one) of Bell's Theorem.

What I like of this mathematical theorem is that it is the strongest I have seen of this kind (Bell type theorem), the most general mathematical premises.

So you are arguing about how good or bad (in your opinion) are his mathematical premises with respect to capturing the conditions and procedures in the real experiments, aren't you?
 

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