- #1
Izy Amisheeva
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- TL;DR Summary
- I ran into a little problem trying to solve the (√x )+ 1 = 0 equation.
Summary: I ran into a little problem trying to solve the (√x )+ 1 = 0 equation.
Obviously there will be no solution in R, so I tried the following
(√x )+ 1 = 0
ei α/2 = ei π
i α / 2 = i pi
so: α = 2 pi
so the solution will be e2 i π
This solution actually works when replaced in the equation.
The question is:
e2 i π works, but 1 which is the same does not work, just as e4 i πdoes not work either.
It seems that of the infinite possibilities of complex representation of 1 only one of them is solution!
Anyone could explain this?
Tanks
Obviously there will be no solution in R, so I tried the following
(√x )+ 1 = 0
ei α/2 = ei π
i α / 2 = i pi
so: α = 2 pi
so the solution will be e2 i π
This solution actually works when replaced in the equation.
The question is:
e2 i π works, but 1 which is the same does not work, just as e4 i πdoes not work either.
It seems that of the infinite possibilities of complex representation of 1 only one of them is solution!
Anyone could explain this?
Tanks
Last edited: