- #1
banfillb
- 25
- 1
Hi All,
So here's the problem. A project I am working on has a composite metal panel assembly, which a previous engineer designed. The metal panels are simply glued to the polystyrene (styrofoam sm). The problem is that the previous engineer did not consider the difference in thermal expansion between the foam and the aluminum, and the foam has begun to fail in shear, and detach from the metal panels.
I'm putting together a report basically laying out the problem, and what I want to find is a temperature gradient which is "allowable" before the styrofoam will shear.
Basically what I have done is set the thermal stress due to restricting thermal expansion (σ=EαdT) equal to the shear strength of the styrofoam (452kPa) and solved for the dT...which ended up coming out to 2.39degC...which seems extremely low to me.
Any suggestions on where I have gone wrong? The only thing I can think of is that I can't directly use the thermal stress due to restriction of thermal expansion directly as a shear force...not sure.
Thanks,
So here's the problem. A project I am working on has a composite metal panel assembly, which a previous engineer designed. The metal panels are simply glued to the polystyrene (styrofoam sm). The problem is that the previous engineer did not consider the difference in thermal expansion between the foam and the aluminum, and the foam has begun to fail in shear, and detach from the metal panels.
I'm putting together a report basically laying out the problem, and what I want to find is a temperature gradient which is "allowable" before the styrofoam will shear.
Basically what I have done is set the thermal stress due to restricting thermal expansion (σ=EαdT) equal to the shear strength of the styrofoam (452kPa) and solved for the dT...which ended up coming out to 2.39degC...which seems extremely low to me.
Any suggestions on where I have gone wrong? The only thing I can think of is that I can't directly use the thermal stress due to restriction of thermal expansion directly as a shear force...not sure.
Thanks,