Short question: Spontaneous emission from Feynman diagrams?

blue2script
Messages
44
Reaction score
0
Hey all,
I am just wondering if one can directly calculate the Einstein coefficient in spontaneous emission of, say, two-level atoms through feynman diagrams? I searched for sources in google but could not find anything.

Thanks a lot for an answer!

Wit best regards,
blue2script
 
Physics news on Phys.org
Maybe I can render the question more precisely: Given a proton in an outer magnetic field I get two energy levels depending on the direction of spin. I can plug the outer field into the Lagrangian. After determing the feynman rules I should be prepared to calculate the decay rate of a proton in the upper energy state.

Am I right?
 
I am not sure if this belongs in the biology section, but it appears more of a quantum physics question. Mike Wiest, Associate Professor of Neuroscience at Wellesley College in the US. In 2024 he published the results of an experiment on anaesthesia which purported to point to a role of quantum processes in consciousness; here is a popular exposition: https://neurosciencenews.com/quantum-process-consciousness-27624/ As my expertise in neuroscience doesn't reach up to an ant's ear...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
This is still a great mystery, Einstein called it ""spooky action at a distance" But science and mathematics are full of concepts which at first cause great bafflement but in due course are just accepted. In the case of Quantum Mechanics this gave rise to the saying "Shut up and calculate". In other words, don't try to "understand it" just accept that the mathematics works. The square root of minus one is another example - it does not exist and yet electrical engineers use it to do...

Similar threads

Replies
15
Views
4K
Replies
1
Views
13K
Replies
4
Views
7K
Replies
2
Views
1K
Replies
3
Views
1K
Replies
38
Views
6K
Back
Top