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cianfa72
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- How to show that a "cross" in the plane is not a topological manifold for any n.
Hi, I've a doubt about the following example in "Introduction to Manifold" by L. Tu.
My understanding is that if one assumes the subspace topology from ##\mathbb R^2## for the "cross", then one can show that the topological space one gets is Hausdorff, second countable but non locally homeomorphic to any ##\mathbb R^n##.
However how can one show that there is not any other topology on the "cross" such that its intersection point ##p## is homeomorphic to some ##\mathbb R^n, n \geq 1## ?
Thank you.
My understanding is that if one assumes the subspace topology from ##\mathbb R^2## for the "cross", then one can show that the topological space one gets is Hausdorff, second countable but non locally homeomorphic to any ##\mathbb R^n##.
However how can one show that there is not any other topology on the "cross" such that its intersection point ##p## is homeomorphic to some ##\mathbb R^n, n \geq 1## ?
Thank you.