Simple spacetime interval question

In summary, the problem involves finding the spacetime interval between two points on a spacetime plot, with the y-axis representing time and the x-axis representing spatial distance. The formula for the interval is given as (c^2(del t)^2 - (del r)^2)^1/2, where c is the speed of light. The attempt at a solution involves calculating the change in r, which represents the spatial distance between the two events. The unit for the interval is typically meters, but it can also be expressed in seconds if c is taken to be 1. The interval is an invariant, meaning it will be the same for all observers regardless of their relative velocities.
  • #1
Eric_meyers
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0

Homework Statement


on a spacetime plot (y-axis) = t (x-axis) = x find the spacetime interval between points (0,0) and (300,700)


Homework Equations


Interval = (c^2(del t)^2 - (del r)^2)^1/2


The Attempt at a Solution


So I can see clearly my del t is 700 (700 - 0 = 700 ) but for the change in r I'm sort of confused about, I'm taking r to be ((700-0)^2 + (300-0)^2)1/2 = 761.577 and thus my spacetime interval number comes out to be 2.1 * 10^11 but I'm unsure if I did the change in r correctly and I'm also not sure what the unit of this number is if it has a unit?
 
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  • #2
The variable r is the spatial distance between the two events, so in this problem, it's equal to x.
 
  • #3
The unit works out to be in meters but my axis's are both in seconds.. I don't quite understand how this can be resolved or what this interval is even telling me.
 
  • #4
You're not using the regular SI units. If you did, time would be measured in seconds, and ct would be in meters, as would be r, so the interval would also be in meters. But it's often convenient to use units where c=1. In this system, time and distance have the same units, usually meters, but you seem to have converted everything to seconds. Think of c as a conversion factor. It tells you 1 second is equal to [itex]3.0\times 10^8[/itex] meters.

The interval is essentially the distance between two points in spacetime. It's an invariant, meaning that all inertial observers will calculate the same value for the interval between two events, regardless of their relative velocities.
 
  • #5
oh so my spacetime interval would then be (700^2-300^2)^1/2 = 632.455 seconds, taking c = 1

Thanks.
 

FAQ: Simple spacetime interval question

1. What is a simple spacetime interval?

A simple spacetime interval is a measure of the distance between two events in spacetime. It is represented by the symbol Δs and is calculated using the Pythagorean theorem with the dimensions of both space and time.

2. How is a simple spacetime interval different from a regular distance measurement?

A simple spacetime interval takes into account the dimensions of both space and time, whereas a regular distance measurement only considers the spatial distance between two points. This is because in spacetime, space and time are intertwined and cannot be separated.

3. What is the significance of a simple spacetime interval in physics?

The simple spacetime interval is a fundamental concept in Einstein's theory of relativity. It is used to calculate the proper time between two events, which is the time measured by an observer who is experiencing the events directly. It also helps to define the concept of causality and the order of events in spacetime.

4. How is a simple spacetime interval affected by the speed of an object?

According to the theory of relativity, the simple spacetime interval between two events is the same for all observers, regardless of their relative motion. However, the perception of time and space can be different for observers moving at different speeds, resulting in a different measurement of the spacetime interval.

5. Can a simple spacetime interval be negative?

Yes, a simple spacetime interval can be negative. This occurs when the time component of the interval is imaginary, meaning it involves the square root of a negative number. This is a result of the mathematical equations used to calculate the spacetime interval and does not have a physical meaning in itself.

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