Solve 2 Equations: 8x-4=9x+6,-x=10

[aarce]

4(2x-1)=3(3x+2)

step 1: 8x-4=9x+6
step 2: -x=10
step 3: ?

 

[MarkFL]

Your thread title and post content show two different problems...which one is correct? And what have you tried? I ask because we can better give you help if we see what you have tried as this gives us an indication of where you're stuck or may be going wrong.

 

[SuperSonic4]

You can treat imaginary parts and real parts separately - they add in the same way "regular" numbers do. We'll be able to help you more if we know where you're stuck :)

 

[GeraldArgue]

Well the title of the thread is different from the post of the thread, it was previous post which I was solved few minutes ago.
But I will solve your problem.
Problem---> (-9+3i)+(4+5i)=?
-9+3i+4+5i=?
Transfer the imaginary no. to one side and real no. to other side
3i+5i=9-4
8i=5
i=5/8
I think my solution will help you.

 

[MarkFL]

Well the title of the thread is different from the post of the thread, it was previous post which I was solved few minutes ago.
But I will solve your problem.
Problem---> (-9+3i)+(4+5i)=?
-9+3i+4+5i=?
Transfer the imaginary no. to one side and real no. to other side
3i+5i=9-4
8i=5
i=5/8
I think my solution will help you.

I believe the OP was supposed to express the sum of the two given complex numbers in the form $a+bi$ where:

\(\displaystyle i\equiv\sqrt{-1}\)

:D