MHB Solve 2sin(2x-π/2) +1 Equation for Sine Curve

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The discussion focuses on solving the equation 2sin(2x - π/2) + 1, specifically addressing the phase shift of the sine curve. The phase shift is determined to be π/2, indicating a rightward movement on the x-axis. Participants emphasize that this shift is represented as a negative value in the equation. Clarification is provided on using the formula c/b to find the phase shift, but some users express confusion about applying it. The conversation highlights the importance of understanding phase shifts in sine functions for accurate graphing and equation solving.
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A sine curve with a period of π , an amplitude of 2, a right phase shift of π/2, and a vertical translation up 1 unit

what i have so far is 2sin(2x- ____ ) +1... i just don't know how to solve the phase shift part...please help and give me the steps. thanks!
 
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krutika said:
A sine curve with a period of π , an amplitude of 2, a right phase shift of π/2, and a vertical translation up 1 unit

what i have so far is 2sin(2x- ____ ) +1... i just don't know how to solve the phase shift part...please help and give me the steps. thanks!

The phase shift is the horizontal shift on the x-axis and is equal to . A movement to the right is minus and to the left is plus.

The way I remember it is that it's opposite from a number line. You can verify this for yourself by checking f(pi/2) and seeing what you get
 
SuperSonic4 said:
The phase shift is the horizontal shift on the x-axis and is equal to $$\frac{\pi}{2}$$. A movement to the right is minus and to the left is plus.

The way I remember it is that it's opposite from a number line. You can verify this for yourself by checking f(pi/2) and seeing what you get

okay but i still don't understand how to find it? like i know the formula is c/b? but i don't get how to find the number?
 

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