Solve Exponential Function x for y: x = (e^y-e^{-y})/2

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To solve the equation x = (e^y - e^{-y})/2 for y in terms of x, it is recognized as a quadratic in e^y. The transformation leads to the equation 2x = e^y - e^{-y}, which can be manipulated to yield e^y = (2x ± √(4x² + 4))/2. This results in the final expression for y as y = ln(x ± √(x² + 1)). The discussion emphasizes providing hints rather than complete solutions to encourage independent problem-solving.
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solve x =(e^y-e^{-y})/2 for y in terms of x

i kinda forgot how to do it~~~sign

any help appreciated

thx


could anyone move this to homework k-12 section thanks

sorry about this
 
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It's a quadratic in e^y, albeit disguised. You'd have no problem solving

2x= t - 1/t
 
2x=e^{y}-e^{-y}
2x\cdot e^{y}=e^{2y}-1
e^{y}=\frac{2x\pm\sqrt{4x^{2}+4}}{2}
y=ln{(x\pm\sqrt{x^{2}+1})}
 
The idea was that the OP would use Matt's suggestion and make the calculations on his/her own.
Please,do not provide full answers,once the 'HINTS' have been given...

Daniel.
 
cool thanks for the hint and the answer
 
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