- #1
TrueStar
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Homework Statement
Solve the exact equation y^3-(14x+2)dx+3xy^2dy=0
Homework Equations
NA
The Attempt at a Solution
I proved these were exact because dM/dy and DN/dx both equal 3y^2
I chose to work with N first and df/dy=3xy^2
Therefore f(x,y)=xy^3+h(x)
I took df/dx of this and got y^3 + h'(x)
I made this equal to the other df/dx so it looks like:
df/dx = y^3+h'(x)=y^3-(14x+2)
h'(x)=-14x+2 and so h(x) is -7x^2+2x (+ constant)
I plugged this into the original problem with h(x) so it now looks like:
f(x,y)=xy^3-7x^2+2x=C
Solving for y, I get y=(-7x^2+2x+C)^(1/3) / x^(1/3)
This is not correct and I don't know what I'm missing here.