Solve for t: Rearrange Equation σ=ωi*t+½α*t^2

  • Thread starter oj600
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In summary, to solve for t in the equation σ = ωi*t + ½ α*t^2, you will need to use the quadratic formula. This will give you the values of t that satisfy the equation.
  • #1
oj600
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Homework Statement



I need to find t in the following:
σ = ωi*t + ½ α*t2 (this is ment to be t squared)

Homework Equations





The Attempt at a Solution


I got:
t + t(squared) = 2 * σ/(ωi * α)

is this then simply
t = sqrt(2 * σ/(ωi * α)) ??
 
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  • #2
σ = ωi*t + ½ α*t^2
You can't write this as:
t + t^2 = 2 * σ/(ωi * α)
You can't divide only 1 half of the equation by something... then you'll just change it.
Like dividing by 1/2 a would give:
t^2 + 2ωi/a*t = 2σ/a
You just can't simplify it like you do.
And your third step is not correct either.

This is a Quadratic Equation ( http://en.wikipedia.org/wiki/Quadratic_equation ), look up how to solve these (you could make use of the quadratic formula).
 
  • #3
Quadratic Formula:
[PLAIN]http://dl.dropbox.com/u/4645835/MATH/Quadratic.gif
 
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FAQ: Solve for t: Rearrange Equation σ=ωi*t+½α*t^2

How do I solve for t in this equation?

To solve for t in this equation, you will need to isolate it on one side of the equation. Begin by subtracting ωi*t from both sides, then divide both sides by ½α to get t by itself.

What do σ, ωi, and α represent in this equation?

σ represents the displacement, ωi represents the initial velocity, and α represents the acceleration.

Can this equation be used for any type of motion?

Yes, this equation can be used for any type of motion as long as there is a constant acceleration.

How do I know which value to substitute for σ, ωi, and α?

You will need to have at least two known values in order to solve for t. Depending on the problem, you may be given the initial velocity, acceleration, and/or displacement. Substituting these values into the equation will allow you to solve for t.

Is there a specific unit for t in this equation?

Yes, t represents time and is typically measured in seconds (s).

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